The force of friction is 300 N
Explanation:
We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. So we can write
![\sum F = ma](https://tex.z-dn.net/?f=%5Csum%20F%20%3D%20ma)
where
is the net force acting on the object
m is its mass
a is its acceleration
For the cart in this problem, we have two forces acting on it:
- The force of push, F = 500 N, forward
- The force of friction,
, backward
So Newton's second law can be rewritten as
![F-F_f = ma](https://tex.z-dn.net/?f=F-F_f%20%3D%20ma)
where
m = 50 kg
is the acceleration of the cart
And solving for
, we find the force of friction:
![F_f = F-ma=500-(50)(4)=300 N](https://tex.z-dn.net/?f=F_f%20%3D%20F-ma%3D500-%2850%29%284%29%3D300%20N)
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