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FrozenT [24]
2 years ago
5

Plz answer I need the answer What is the goal of technology?

Chemistry
2 answers:
Sloan [31]2 years ago
7 0
I think the answer is C
iVinArrow [24]2 years ago
6 0

Answer:

The goal is to improve the way which we live,to make our lives easier by reducing paper work.It is important because technology helps keep our information safe.

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What are the products in a chemical equation located?
Arturiano [62]

Answer:

The right-hand side

Explanation:

A chemical equation describes a chemical reaction. Products are the end-result of the reaction and are written on the right-hand side of the equation.

7 0
3 years ago
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if i poured green solution into another test tube and added some copper pieces to the solution will a displacment action occur
Angelina_Jolie [31]

Depends on what kind of ions are present in the green solution

Explanation:

Cr3+, a famous green ion can obviously be displayed by a Cu2+ ion

https://brainly.in/question/47911070

8 0
1 year ago
Imagine you are given a mystery element. It is , however a discovered and known element . You may perform a maximum of two obser
frutty [35]
I would choose count of electron shells and count of valence electrons. The electron configuration of each element is fixed and can be used to determine the element's identity. By counting the electron shells, you can have an idea which part of the periodic table the mystery element lies, and by determining the number of valence electrons (outermost shell), you can pinpoint the exact identity of the mystery element.
4 0
3 years ago
How many significant digits are there in the measurement 50,600 mg A)4 B)5 C)6 D)7
Arte-miy333 [17]

Five. The measurement 50,600 mg has five significant digits.

I presume that you are using the comma as a decimal separator.

The <em>rules for significant figures</em> are
1. Nonzero digits are always significant.
2. Any zeros between two significant digits are significant.
3. Final or trailing zeros are significant only if they are to the right of a decimal point.

• According to Rule 1, the <em>5 and 6</em> are significant.
• According to Rule 2, the <em>0 between the 5 and 6</em> is significant
• According to Rule 3, the <em>final two zeros</em> are significant.

Thus, there are five significant digits in the measurement 50,600 mg.

Note: If the comma is a thousands separator, the number has only three significant digits.

7 0
3 years ago
Read 2 more answers
The molar absorptivity for aqueous solutions of phenol at 211 nm is 6.17x103L/mol/cm. Calculate the linear range of phenol conce
Scilla [17]

Explanation:

The given data is as follows.

          \lambda = 211 nm,          \sum = 6.17 \times 10^{3} mol/L/cm

           l = 1 cm,             7% < Transmittance < 85%

Suppose the aqueous solution follows Lambert-Beer's law. Therefore,

                   Absorbance = -log \frac{\text{Percentage transmittance}}{100}

Hence, for 7% transmittance the value of absorbance will be as follows.

                  Absorbance = -log \frac{7}{100}

                           A_{1} = 1.155

For 85% transmittance the value of absorbance will be as follows.

                 Absorbance = -log \frac{85}{100}

                           A_{2} = 0.07058

According to Lambert-Beer's law.

                  A = \sum \times l \times C

where,       A = absorbance

                 \sum = molar extinction coefficient

                 C = concentration

Therefore, concentration for 7% absorbance is as follows.

                    A_{1} = \sum \times l \times C_{1}

                  C_{1} = \frac{1.155}{6.17 \times 10^{3} \times 1}

                                  = 0.187 \times 10^{-3} mol/L

                                  = 0.187 mmol/L

Concentration for 85% absorbance is as follows.

                   A_{2} = \sum \times l \times C_{2}

                  C_{2} = \frac{0.07058}{6.17 \times 10^{3} \times 1}

                                  = 0.01144 \times 10^{-3} mol/L

                                  = 0.01144 mmol/L

Thus, we can conclude that linear range of phenol concentration is 0.01144 mmol/L to 0.187 mmol/L.

6 0
3 years ago
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