Answer:
0.110625 g of Ni
Explanation:
The first step in solving this problem is to put down the accurate chemical reaction equation.
Ni(s) + 2HCl(aq) ---> NiCl2(aq) + H2(g)
Secondly, we obtain the amount of HCl that reacted from the information provided.
Volume of HCl (V)= 25 ml
Concentration of HCl (C)= 0.15 mol/L
Then, to find the number of moles of HCl (n);
n= CV
Substitution values
n= 25/1000 × 0.15
n= 3.75 ×10^-3 moles
Mass of 3.75 ×10^-3 moles of HCl = number of moles × molar mass
Molar mass of HCl= 36.5 gmol-1
Therefore;
Mass of HCl = 3.75 ×10^-3 moles × 36.5 gmol-1
Mass of HCl= 0.136875 g of HCl
Thirdly we determine the mass of Ni reacted;
If 1 mole of Ni reacted with 2 moles of HCl according to the reaction equation
Then x moles of Ni reacts with 3.75 ×10^-3 moles of HCl
x= 1 × 3.75 ×10^-3 moles/ 2
x= 1.875 × 10^-3 moles of Ni
Mass of Ni= 1.875 × 10^-3 moles of Ni × 59 gmol-1
Mass of Ni= 0.110625 g of Ni
