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sashaice [31]
2 years ago
6

Helppppp meeeeee pleaseeeeeeeee

Physics
1 answer:
vfiekz [6]2 years ago
5 0
I think it c or d it one I those
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Consider dropping a ball from rest. This ball moves from astate of high gravitational potential energy to one of lowgravitationa
Leni [432]

Answer:

From the negative to the positive cable.

Explanation:

The electrons have negative charge, which means that the negative terminal of the battery will suply the electrons, thus they are present in excess on the negative cable and will jump from it to the positive cable. This current direction is called real current.

3 0
3 years ago
Describe a technology used in space exploration.
Alex777 [14]

Answer:

High speed optical communication technology

To be able to communicate from the space to the earth and from earth to space is one of the most essential features required during space exploration.

Explanation:

Space exploration involves going into the space, beyond the earth's atmosphere. Landing on other planets and studying their details, going into deeper space beyond the planets to discover new cosmic events or structures is all a part of space exploration.

The key to analyse the studies and observations is being able to communicate the data collected, photos taken etc to the launch centers or space centers on earth. The space centers on earth should also be able to communicate with the persons or the satellites in space.

This is made possible using the optical communication technology which involves the use of optical fibers, lasers etc, since high speeds are more efficient during communication

3 0
3 years ago
weight of Ali is 500andN.he is standing on the ground with an area of 0.025 m^2 area .we can find pressure under his feet. what
Inessa05 [86]

Answer:

20000 Pa

Explanation:

Pressure is defined as the force per unit area.

Mathematically : P =F/A    where F is force and A is area

Force = 500 N

Area= 0.025 m²

P= 500/0.025

P= 20000 Pa

8 0
2 years ago
An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the
zzz [600]

Answer:

The magnitude of the electric flux is 3.53\ N-m^2/C

Explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

Area A= 1.65 m^2

We need to calculate the flux

Using formula of the magnetic flux

\phi=E\cdot A

\phi = EA\cos\theta

Where,

A = area

E = electric field

Put the value into the formula

\phi=2.35\times1.65\times\cos 25^{\circ}

\phi=2.35\times1.65\times0.91

\phi=3.53\ N-m^2/C

Hence, The magnitude of the electric flux is 3.53\ N-m^2/C

8 0
3 years ago
Determine the maximum r-value of the polar equation r =3+3 cos 0
AURORKA [14]

[r] =6  

Solve for r by simplifying both sides of the equation, then isolating the variable.

<em> </em>I hope this makes sense


8 0
2 years ago
Read 2 more answers
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