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marta [7]
3 years ago
10

Calculate the amount, in grams, of an original 300 gram sample of potassium 40 remaining after 3.9 billion years.

Physics
1 answer:
Schach [20]3 years ago
3 0
71718 88.
1919910
So just if
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What is the wavelength (in air) of a 13.0 khz vlf radio wave?
bonufazy [111]
Since,
Speed = Frequency * WaveLength

=> WaveLength = Speed / Frequency --- (A)

Frequency = 13.0 kHz.
As the radio waves are electromagnetic waves, their speed is equals to the speed of light. Therefore,
Speed = C = 3 *  10^{8}  m/ s^{2}

Plug in the values in equation(A):

A => WaveLength = \frac{3 * 10^{8}}{13*10^{3}}

Ans: Wavelength = 23.077 kilometers.
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5 0
3 years ago
40 POINTS!!! PLEASE HELPP!!!
NeX [460]

Answer:

A

Explanation:

if it was B it would say from one to another to another

7 0
3 years ago
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Please help me. Thanks
belka [17]
Both mass and weight
4 0
3 years ago
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What will happen when a light bulb is removed from the circuit below, leaving a gap?
Charra [1.4K]

Answer:

The remaining light bulbs will go out.

Explanation:

The light bulb that was taken out routed power to the other light bulbs, there for, not giving power to the next light bulbs will make them turn off or, "go out". This may be incorrect, as you did not provide a picture of the circuit.

7 0
3 years ago
Read 2 more answers
Please help me guys never mind the calculations ​
vlada-n [284]

The shape is connected in parallel so;

5.1) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{2}  +  \frac{1}{3}  \\  \frac{1}{R}  =  \frac{3 + 2}{6}  =  \frac{5}{6}  \\ R =  \frac{6}{5}  = 1.2 \:  \: ohm

5.2) Ans;

\frac{1}{R}  =  \frac{1}{R1} +  \frac{1}{R2}   \\  \frac{1}{R}  =  \frac{1}{8}  +  \frac{1}{10}  \\  \frac{1}{R}  =  \frac{5 + 4}{40}  =  \frac{9}{40}  \\ R =  \frac{40}{9}  = 4.4 \:  \: ohm

I hope I helped you^_^

7 0
3 years ago
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