superman is flying 54.5 m/s when he sees a train about to fall into a river 850 m away . he must reach the train in 4.22 s

Leto [7]

Since it's a projectile being launched the only force acting upon it is gravity, since the object is in free fall once it's launched

so to calculate time you'd utilize the general formula of
$xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}$
and then solve using time and make it into the y axis, so change the x's to y's, which will change a to g.
since Vyi is always usually 0, you can drop that out of this equation so the formula to find time would be
$t = \sqrt{ \frac{2(y)}{g} }$
So you'll plug in and it'll be
$t = \sqrt{ \frac{2( - 49m)}{ - 9.81 \frac{m}{s {}^{2} } } }$
to find the maximum height you'll have to do some trigonometry to solve it.
To make it easier draw a triangle
put the 60° mark as shown in the picture.
Then you'll need to find the hypotenuse or horizontal to find the vertical
So the hypotenuse would be the 113m/s
so then you'll use
$\ \sin( 60) = ( \frac{o}{h})$

plug in the numbers
$113( \ \sin (60) ) = o$
now that you have the vertical

use the formula
${vf}^{2} = {vi}^{2} + 2gd$
solve for d which will give you the hypotenuse
$d = { (-vertical \frac{m}{s} )}^{2} \div 2( - 9.81 \frac{m}{ {s}^{2} } )$
The "vertical" is what you found in the previous step.
Vf^2 is equal to 0 so you can just drop that number out since it's 0
then once you have that then youre not done yet
since you're on a cliff of 49 m you'll have to add 49m to the previous answer that you found d to find the maximum height.

I hope this helps!

6 0

3 years ago

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time

Tju [1.3M]

Answer:

675m

Explanation:

Given parameters:

Initial velocity = 0m/s

Acceleration = 6m/s²

Time = 15s

Unknown:

Distance traveled by the body = ?

Solution:

To solve this problem; we use the expression;

S = ut + $\frac{1}{2}$ at²

Where u is the initial velocity

t is the time

a is the temperature

Insert the parameters and solve;

S = 0 x 15 + $\frac{1}{2}$ x 6 x 15²

S = 675m

5 0

3 years ago

How much heat is required to convert 0.3 kilogram of ice at 0°C to water at the same temperature

Grace [21]

Answer:

100,200J of heat is required to convert 0.3kg of ice of 0°C to water at same temperature.

Explanation:

Heat = mass * lf

Latent heat of fusion (lf) of water is 334J/g

Heat = 300g * 334 J/g

Heat = 100,200J of heat

6 0

3 years ago

Read 2 more answers

Is an electron an antiparticle, boson, lepton, or hadron?

Masteriza [31]

Answer:

An electron is a lepton

4 0

3 years ago

A 48-kg woman pushes a 12-kg grocery cart with a force of 24 N. What is the magnitude of the force that the grocery cart exerts

Nata [24]

The correct answer is B. 24 N.

To figure out the exact force the cart exerts on the woman, we have to use Newton's third law of motion. Newton's third law of motion states that every action has an equal and opposite reaction. This means that if object 1 exerts a force on object 2 , object 2 will exert an equal but opposite force on object 1.

This law allows us to ignore the masses of the chart and the women and focus on the pairs of forces the woman and the chart apply to each other. Since the woman exerts a force of 24 N on the chart, the chart will exert a force of 24 N on the woman.

The correct answer is B. 24 N.

4 0

3 years ago