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Thepotemich [5.8K]
3 years ago
12

Ball of mass 200g is moving with a speed of 17m/s. What is its deBroglie wavelength?

Physics
2 answers:
Tresset [83]3 years ago
6 0

Answer: 1.94\times 10^{-34}m

Explanation:

Formula used : \lambda=\frac{h}{m\times v}

where,

\lambda = wavelength  =?

h = Planck's constant = 6.626\times 10^{-34}Js

m = mass  = 200 g = 0.2kg

v = velocity  =17m/s

Now put all the given values in this formula, we get

\lambda=\frac{6.626\times 10^{-34}Js}{0.2kg\times 17m/s}=1.94\times 10^{-34}m

The de Broglie wavelength for the ball is 1.94\times 10^{-34}m

miv72 [106K]3 years ago
4 0

Answer:

The deBoglie  wavelength is 1.95 ×10⁻³⁴ m

Explanation:

To calculate the deBoglie wavelength, we use the formula;

λ = h/ρ

where  ρ is    the momentum

So first we will find the momentum, momentum(ρ) = mv

m is the mass and v is the velocity, the mass must be in kilogram

So from the question, mass (m) = 200g converting this to kilogram, mass(m) =200/1000=0.2kg

v =17m/s

We can now substitute our values in ρ = mv and solve for momentum

Momentum(ρ) = mv

                        =0.2×17

                        =3.4 kgm/s

ρ  = 3.4 kgm/s

We can now proceed to find the deBoglie wavelength

deBoglie wavelength(λ) = h/ρ              h is a constant = 6.626×10⁻³⁴ j.s

deBoglie  wavelength(λ) = h/ρ

                                         = 6.626×10⁻³⁴/3.4

                                           =1.95 ×10⁻³⁴ m

Therefore the deBoglie  wavelength is 1.95 ×10⁻³⁴ m

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• products

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<em />

Now we solve the system of equations,

2<em>a</em> = 2<em>b</em> … … … [1]

4<em>a</em> = 2<em>d</em> … … … [2]

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<em />

From [1] we immediately have

<em>a</em> = <em>b</em>

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2<em>a</em> = <em>d</em>

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3<em>a</em> = 2<em>c</em> + 2<em>a</em>

<em>a</em> = 2<em>c</em>

<em />

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• <em>b</em> = 2

• <em>d</em> = 2×2 = 4

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2 NH₄NO₃   ⇒   2 N₂ + O₂ + 4 H₂O

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