Question

astone is thrown upwards with an initial velocity of 25m/s atan angle of 30 to the ground.what is the work out the stones horizantal range ?

Answer 1

Answer:

Range is 62.5 metres

Explanation:

Time of flight

$t = \frac{2u \sin( \theta) }{g}$

for range, acceleration is zero

from second newton's equation:

$S = ut + \frac{1}{2} {at}^{2}$

but a = 0:

let range be x:

$x = ut \\ x = \frac{2 {u}^{2} \sin( \theta) }{g} \\ \\ x = \frac{ \{2 \times 25 {}^{2} \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres$

[ taken g to be 10 m/s² ]