Answer:
0.0002 M
Explanation:
<em>The molarity of the HCl required would be 0.0002 M.</em>
First, let us consider the balanced equation of the reaction:
<em>Stoichiometrically, 1 mole of </em>
<em> reacts with 2 moles of </em>
<em> for a complete neutralization reaction.</em>
Recall that: mole = 
Mole of 0.550 g sodium oxalate = 0.550/134 = 0.0041 mole
<em>If 1 mole </em><em> requires 2 moles HCl, then 0.0041 mole will require</em>:
0.0041 x 2 = 0.0082 mole HCl
Volume of the HCl = 40.95 L
Molarity = mole/volume
Hence, molarity of the HCl = 0.0082/40.95 = 0.0002 M
the answer will there for be ironic
Since the volume is constant,
p1/t = p2/ t
210/120 = p2/150
p2= 262.5kpa
It’s #2 because I saw on edigunity 2020
Answer:
4.2 x 10⁴ mL
Explanation:
Data Given:
Density (d) of air = 1.19 x 10⁻³g/mL
Mass of the air (m) = 50 g
Volume of the air (V) = ?
Solution:
Formula will be used
d = m/V
As we have to find volume so rearrange the above equation
V = m/d . . . . . . . . . . . (1)
Put values in above equation 1
V = 50 g / 1.19 x 10⁻³g/mL
V = 4.2 x 10⁴ mL
So,
volume of dry air = 4.2 x 10⁴ mL
