Answer:
wavelength= 5.35×10cm=0.535m
f= 16000hz
v= wavelength × f= 0.535×16000=8560m/sec
The magnitude of the current in wire 3 is 2.4 A and in a direction pointing in the downward direction.
- The force per unit length between two parallel thin current-carrying
and
wires at distance ' r ' is given by
....(1) .
- If the current is flowing in both wires in the same direction, and the force between them will be the attractive force and if the current is flowing in opposite direction in wires then the force between them will be the repulsive force.
A schematic of the information provided in the question can be seen in the image attached below.
From the image, force on wire 2 due to wire 1 = force on wire 2 due to wire 3

Using equation (1) , we get

I₃ = 2.4 A and the current is pointing in the downward direction
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Answer:
These regions are known as compressions and rarefactions respectively. The compressions are regions of high air pressure while the rarefactions are regions of low air pressure.
Explanation:
Answer: 4.
Explanation:
Use formula v = d / t, where v = speed, d = distance and t = time.
v = 10 / 2.5
v = 4.
Answer:B
Explanation:
For work to be done, the object must move some distance as a result of a force