All categories

3 years ago

A racing car going a 20 m/s stops in a distance of 20 m.What is its acceleration?

Physics

1 answer:

aleksklad [387]3 years ago

3 0

step by step

formular v^2 = u^2+2as

stop v = 0

0 = 400+2a(20)

-400=40a

a = -10 m/s^2

ans affect acceleration is 10 m/s^2

You might be interested in

The acceleration due to gravity on the Moon's surface is

Molodets [167]

Answer:

50 lb

Explanation:

Given,

The weight of astronaut's life support backpack on Earth (w) = 300 lb

Acceleration due to gravity on Earth (g) = 9.8 m/s²

Acceleration due to gravity on Moon = g'

$g'=\frac{g}{6}$

We know that weight of an object on Earth is,

$w = m\times g$

$m = \frac{w}{g}$

Similarly, weight on Moon will be

$w' = m\times g'$

$w' = \frac{w}{g}\times\frac{g}{6}$

$w' = \frac{300}{6}$

$w' = 50$

Thus the astronaut's life support backpack will weigh 50 lb on Moon.

7 0

3 years ago

A piano tuner sounds two strings simultaneously. One has been previously tuned to vibrate at 293.0 Hz. The tuner hears 3.0 beats

ololo11 [35]

Answer:

Part a)

$f_B = 290 Hz$

Part B)

percentage increase is

$percentage = 1.38$ %

Explanation:

Part a)

As we know that the beat frequency is

$f_A - f_B = 3$

after increasing the tension the beat frequency is decreased and hence the tension in string B will increase

So we have

$293 - f_B = 3$

$f_B = 290 Hz$

Part B)

percentage increase in the tension of the string will be given as

$f_A - f_B' = 1$

$f_B' = 292 Hz$

now we have

$f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}$

so we have

$T_1 = C (290)^2$

$T_2 = C(292)^2$

so we have

$\frac{\Delta T}{T} = \frac{292^2 - 290^2}{290^2}$

percentage increase is

$percentage = 1.38$

4 0

3 years ago

CAN SOMEONE HEELLLLLLLLLP MEEEEEEE

Soloha48 [4]

Its B , the definition of cardiovascular endurance is <span>the ability of the heart, lungs and blood vessels to deliver oxygen to your body tissues.</span>

7 0

3 years ago

Read 2 more answers

How far from the base of the platform does she land?

seropon [69]

When Janet leaves the platform, she's moving horizontally at 1.92 m/s. We assume that there's no air resistance, and gravity has no effect on horizontal motion. There's no horizontal force acting on Janet to make her move horizontally any faster or slower than 1.92 m/s.

She's in the air for 1.1 second before she hits the water.

Moving horizontally at 1.92 m/s for 1.1 second, she sails out away from the platform

(1.92 m/s) x (1.1 sec) = <em>2.112 meters</em>

3 0

3 years ago

The area in which the attraction and the repulsion of a magnet's poles are felt is a(n)

docker41 [41]

The are is called a magnetic field.

8 0

3 years ago

Read 2 more answers

A racing car going a 20 m/s stops in a distance of 20 m.What is its acceleration?​

A racing car going a 20 m/s stops in a distance of 20 m.What is its acceleration?