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Korolek [52]
3 years ago
9

A racing car going a 20 m/s stops in a distance of 20 m.What is its acceleration?​

Physics
1 answer:
aleksklad [387]3 years ago
3 0

step by step

formular v^2 = u^2+2as

stop v = 0

0 = 400+2a(20)

-400=40a

a = -10 m/s^2

ans affect acceleration is 10 m/s^2

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Answer:

The time where the avergae speed equals the instaneous speed is T/2

Explanation:

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v_{ave} = \frac{1}{T}\int\limits^T_0 {v(t)} \, dt

v_ave = v0+a(T/2)

We can esaily note that when <u><em>t=T/2</em></u><u><em> </em></u>

v(T/2)=v_ave

Now we want to know where the car should be, the osition of the car is:

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The work done on the suitcase by Russell is given by the formula

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Substituting the given values,

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