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3 years ago

What is the voltage measured with a voltmeter across a wire in a circuit?

Physics

2 answers:

Law Incorporation [45]3 years ago

6 0

<h3>Answer;</h3>

The voltage is zero

<h3>Explanation;</h3>

Voltage is the potential difference between two points in a circuit or the electromotive force in a given circuit and is expressed in volts (V).

Voltage is measured by a device called voltmeter that is always connected in parallel with the current source.

When voltage is measured between two points on a wire in a circuit with zero or no resistance in between the two points then the voltage will be zero. From the ohm's Law, voltage is given the product of resistance and current and thus if the resistance is zero then the voltage will be zero.

Volgvan3 years ago

6 0

C) The voltage is zero.

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Answer:

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2 years ago

Consider a 20 cm thick granite wall with a thermal conductivity of 2.79 W/m·K. The temperature of the left surface is held const

kozerog [31]

Answer:

The right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

Explanation:

Thickness of the wall is L= 20cm = 0.2m

Thermal conductivity of the wall is K = 2.79 W/m·K

Temperature at the left side surface is T₁ = 50°C

Temperature of the air is T = 22°C

Convection heat transfer coefficient is h = 15 W/m2·K

Heat conduction process through wall is equal to the heat convection process so

$Q_{conduction} = Q_{convection}$

Expression for the heat conduction process is

$Q_{conduction} = \frac{K(T_1 - T)}{L}$

Expression for the heat convection process is

$Q_{convection} = h(T_2 - T)$

Substitute the expressions of conduction and convection in equation above

$Q_{conduction} = Q_{convection}$

$\frac{K(T_1 - T_2)}{L} = h(T_2 - T)$

Substitute the values in above equation

$\frac{2.79(50- T_2)}{0.2} = 15(T_2 - 22)\\\\T_2 = 35.5^\circC$

Now heat flux through the wall can be calculated as

$q_{flux} = Q_{conduction} \\\\q_{flux} = \frac{K(T_1 - T_2)}{L}\\\\q_{flux} = \frac{2.79(50 - 35.5)}{0.2}\\\\q_{flux} = 202.3W/m^2$

Thus, the right wall surface temperature and heat flux through the wall is 35.5°C and 202.3W/m²

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