Question

If SK=13x-5,KY=2x+9, and SY=36-x find each value

Answer 1

SY = SK+KY

36–x = (13x-5) + (2x+9)

13x+2x+x= 36+5-9

16x= 32

x= 32/16

x= 2

x= 2

SK= 13x-5 = 13(2)-5=26-5=21

SK=21

KY=2x+9=2(2)+9=4+9=13

KY=13

SY=36-X= 36-2=34

SY= 34

SO;

X=2

Sk=21

KY=13

SY=34

I hope I helped you^_^

Answer 2

Answer:

SY = SK + KY

(36 - X) = (13X - 5) + (2X + 9)

36 - X = 13X - 5 + 2X + 9

36 + 5 - 9 = 13X + 2X + X

32 = 16X

32/16 = 16/16

X = 2

ii)SK = 13X - 5

SK = 13(2) - 5

SK = 21 units

iii) KY = 2X + 9

KY = 2(2) + 9

KY = 13

iv) SY = 36 - X

SY = 36 - 2

SY = 34