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3 years ago

Two most abundant elements in Earth's core are

1 answer:

7 0

Iron accounts for about 86% of the Earth's core and Silicon is next at only 6%. Iron is by far the most abundant element in the Earth's core.

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Na-23 has 12 neutrons. What is it’s atomic number?

Dennis_Churaev [7]

Answer:

Explanation:

The atomic number for Na will always be the same regardless of the number of neutrons.

7 0

4 years ago

Who was the inventor of the lightbulb?

Nuetrik [128]

Answer: thomas edison

Explanation:

7 0

3 years ago

Balance the following equation on scrap paper:<br> AIF3+Li2O → Al2O3 + LiF

Oxana [17]

Answer:

2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF

Explanation:

AlF₃ + Li₂O —> Al₂O₃ + LiF

The above equation can be balanced as follow:

AlF₃ + Li₂O —> Al₂O₃ + LiF

There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:

2AlF₃ + Li₂O —> Al₂O₃ + LiF

There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:

2AlF₃ + Li₂O —> Al₂O₃ + 6LiF

There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:

2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF

Thus, the equation is balanced..!

8 0

3 years ago

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

3 years ago

Match the following equation with the type of chemical reaction. Question 6 options: H2 + O2 ---> H2O HBr ---> H2 + Br2 HC

kenny6666 [7]

Hello there!

1. Synthesis: 2H₂ + O₂ → 2H₂O
2. Decomposition: 2HBr → H₂ + Br₂
3. Single-Replacement: 2Al + 3H₂SO₄ → 3H₂ + Al₂(SO₄)₃
4. Double-Replacement: 2HCl + 2NaOH → 2H₂O + 2NaCl
5. Combustion: 2C₂H₆ + 7O₂ → 6H₂O + 4CO₂

I hope this helps!
Brady

5 0

3 years ago