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RideAnS [48]
3 years ago
11

Match the following equation with the type of chemical reaction. Question 6 options: H2 + O2 ---> H2O HBr ---> H2 + Br2 HC

l + NaOH ---> H2O + NaCl Al + H2SO4 ---> H2+ Al2(SO4)3 C2H6 + O2 ---> H2O + CO2 1. Synthesis 2. Decompostion 3. Single- Displacement 4. Double- Replacement 5. Combustion
Chemistry
1 answer:
kenny6666 [7]3 years ago
5 0
Hello there!

1. Synthesis: 2H₂ + O₂ → 2H₂O
2. Decomposition: 2HBr → H₂ + Br₂
3. Single-Replacement: 2Al + 3H₂SO₄ → 3H₂ + Al₂(SO₄)₃
4. Double-Replacement: 2HCl + 2NaOH → 2H₂O + 2NaCl
5. Combustion: 2C₂H₆ + 7O₂ → 6H₂O + 4CO₂

I hope this helps!
Brady

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The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
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