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3 years ago

Which is a physical property of milk?

Chemistry

1 answer:

shtirl [24]3 years ago

3 0

Answer:

Milk boils at about 212 F (100 c)

Explanation:

A physical property is a property in which a chemical change is not nessecary to undergo to know about.

Since all the other options require a chemical change to know, they are not physical properties.

The third option is a physical property because it does not require a chemical change to know.

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Suppose a 500.mL flask is filled with 1.9mol of NO3 and 1.6mol of NO. The following reaction becomes possible: NO3gNOg 2NO2g The

never [62]

There is an error in the first sentence of the question; the right format is:

Suppose a 500.mL flask is filled with 1.9mol of NO3 and 1.6mol of NO2.

It should be NO2 and not NO.

Answer:

The equilibrium molarity of NO = 0.21695 m

Explanation:

Given that :

the volume = 500 mL = 0.500 m

number of moles of $NO_3 = 1.9 \ mol$

number of moles of $NO_2 = 1.6 \ mol$

Then we can calculate for their respectively concentrations as :

$[NO_3] = \frac{number \ of \ moles}{volume}$

$[NO_3] = \frac{1.9}{0.500}$

$[NO_3] = 3.8 \ M$

$[NO_2] = \frac{number \ of \ moles}{volume}$

$[NO_2] = \frac{}{} \frac{1.6}{0.500}$

$[NO_2] = 3.2 \ M$

The chemical reaction can be written as:

$NO_3_{(g)} + NO_{(g)} \to 2NO_2_{(g)}$

The ICE table is as follows;

$NO_3_{(g)} + NO_{(g)} \to 2NO_2_{(g)}$

Initial 3.8 - 3.2

Change +x x -2x

Equilibrium 3.8+x +x 3.2 - 2x

$K_c=\frac{[NO_2]^2}{[NO_3][NO]}$

$where \ K_c = 8.33$

$8.33 = \frac{(3.2-2x)^2}{(3.8+2x)x} \\ \\ 8.33 = \frac{(3.2-2x)^2}{(3.8x+2x^2)}$

$8.33(3.8x + 2x^2) = (3.2-2x)^2 \\ \\ 31.654x + 16.66x^2 = (3.2-2x)(3.2-2x) \\ \\ 31.654x + 16.66x^2 = 10.24 - 12.8x +4x^2 \\ \\ 10.24 - 44.454x -12.66 x^2 = 0 \\ \\ 12.66x^2 +44.454x -10.24 = 0$

Using quadratic formula;

$\frac{-b\pm \sqrt{(b)^2-4ac} }{2a}$

= $\frac{-(44.454) + \sqrt{(44.454)^2-4(12.66)(-10.24)} }{2(12.66)} \ \ OR \ \ \frac{-(44.454) - \sqrt{(44.454)^2-4(12.66)(-10.24)} }{2(12.66)}$

= 0.21695 OR -3.7283

Going by the positive value;

x = 0.21695

$[NO_3] = 3.8 +x = 3.8 + 0.21695$

= 4.01695 m

[NO] = x = 0.21695 m

$[NO_2] = 3.2 +x = 3.2 + 0.21695$

= 3.41695 m

3 0

3 years ago

What is the pressure of the ideal gas when the volume is decreased to 4.0 L and the temperature is increased to 265 K?

jonny [76]

It is an ideal gas therefore we can use the ideal gas equation to solve the problem. The ideal gas equation is expressed as PV = nRT. First, we solve the amount of the gas in moles using the said equation and the first conditions.

(2.0 atm) (5.0 x 10^3 cm^3) = n (82.0575 atm.cm^3/mol.K)(215 K)
n=0.5668 mol

Using the second conditions given, we obtain the new pressure.
P (4.0 x 10^3) = 0.5668 x <span>82.0575 x 265
P= 3.08 atm</span>

8 0

3 years ago

NEED ASAP WILL GIVE BRAINLIST

inysia [295]

Answer:

It have 31 electrons

4 0

3 years ago

On a class trip to the coast, you and your lab partner find a rock in the spot marked in red on the diagram. You show your teach

NNADVOKAT [17]

Cause it’s is the same

8 0

3 years ago

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Solution made up of a

Vadim26 [7]

Answer:

solute and solvent

Explanation:

Because solutes dissolves in solvent to form a solution

5 0

3 years ago