What is one property of salts?

2.0 moles of a monatomic ideal gas undergoes an isobaric process in which the temperature changes from 260 k to 320 k. what is t

Alik [6]

The change in the internal energy of the gas is 1.5×10∧3 J.

The internal energy of an ideal gas is directly proportional to the temperature of the gas:

ΔE = 3/2 × n × R × ΔT

ΔT = 320 K - 260 K

ΔT = 60 K; change of the temperature

n = 2.0 mol: amount of a monatomic ideal gas

R = 8.1 J/mol×K;the ideal gas constant

ΔE = 3/2 × 2 mol × 8.1 J/mol×K × 60 K

ΔE = 1500 J

ΔE = 1.5×10∧3 J; the internal energy of the gas

Isobaric process is a type of process in which the pressure of the system stays constant.

More about an isobaric process: brainly.com/question/28106078

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4 0

1 year ago

Use the periodic table to identify the element with the electron configuration 1s²2s²2p⁴. Write its orbital diagram, and give th

natta225 [31]

Answer:

1. Orbital diagram

2p⁴ ║ ↑↓ ║ "↑" ║ ↑

2s² ║ ↑↓ ║

1s² ║ ↑↓ ║

2. Quantum numbers

n = 2,
l = 1,

$m_{l}$ = 0,

$m_{s}$ = +1/2

Explanation:

The fill in rule is:

Follow shell number: from the inner most shell to the outer most shell, our case from shell 1 to 2

Follow the The Aufbau principle, 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p
Hunds' rule: Every orbital in a sublevel is singly occupied before any orbital is doubly occupied. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).

So, the orbital diagram of given element is as below and the sixth electron is marked between " "

2p⁴ ║ ↑↓ ║ "↑" ║ ↑

2s² ║ ↑↓ ║

1s² ║ ↑↓ ║

The quantum number of an electron consists of four number:

n (shell number, - 1, 2, 3...)
l (subshell number or orbital number, 0 - orbital s, 1 - orbital p, 2 - orbital d...)
$m_{l}$ (orbital energy, or "which box the electron is in"). For example, orbital p (l = 1) has 3 "boxes", it was number from -1, 0, 1. Orbital d (l = 2) has 5 "boxes", numbered -2, -1, 0, 1, 2
$m_{s}$ (spin of electron), either -1/2 or +1/2

In our case, the electron marked with " " has quantum number

n = 2, shell number 2,
l = 1, subshell or orbital p,

$m_{l}$ = 0, 2nd "box" in the range -1, 0, 1

$m_{s}$ = +1/2, single electron always has +1/2

3 0

4 years ago

P-fluoroanisole reacts with sulfur trioxide and sulfuric acid. Draw the major product of this substitution reaction; if applicab

Ipatiy [6.2K]

Answer: (Structure attached).

Explanation:

This type of reaction is an aromatic electrophilic substitution. The overall reaction is the replacement of a proton (H +) with an electrophile (E +) in the aromatic ring.

The aromatic ring in p-fluoroanisole has two sustituents, an halogen and a methoxy group, which are ortho-para directing substituents.

Aryl sulfonic acids are easily synthesized by an electrophilic substitution reaction aromatic using sulfur trioxide as an electrophile (very reactive).

The reaction occurs in three steps:

The attack on the electrophile forms the sigma complex.
The loss of a proton regenerates an aromatic ring.
The sulfonate group can be protonated in the presence of a strong acid (H₂SO₄).

Normally, a mixture of ortho-para substituted products would be obtained. However, since both para positions are occupied, only the ortho substituted product is obtained here.

8 0

3 years ago

When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 27.6 g of carbon were burned in the presence of

In-s [12.5K]

Answer:

The answer to your question is: 101.2 g of CO2

Explanation:

C = 27.6 g

O₂ = 86.5 g remained 12.9 g

O₂ that reacted = 86.5 - 12.9 = 73.6 g

C + O₂ ⇒ CO₂ The equation is balanced

27.6 73.6 ?

MW 12 32 44

Rule of three

12 g of C------------------ 44 g CO2

27.6 g C ------------------ x

x = 27.6(44)/12 = 101.2 g of CO2

32 g of O2 --------------- 44 g of CO2

73.6 g of O2 ------------ x

x = 73.6(44)/32 = 101.2 g of CO2

6 0

3 years ago

Which description is of the man in the graveyard?

vekshin1

B is the answer to ur question

5 0

4 years ago

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