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anygoal [31]
3 years ago
10

A mass is hanging from the end of a horizontal bar that pivots around an axis through its center, but it is being held stationar

y. The bar is then released and begins to rotate. As the bar rotates from horizontal to vertical, the magnitude of the torque on the bar: ________
Physics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

The torque decreases because as the hanging mass goes down, the moment arm about the pivot point decreases. Since the torque is directly proportional to the length of the moment arm, torque decreases.

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There would be more hours of sunlight at the equator

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Be-36 what hull type is best for use on ponds, small lakes and calm rivers?
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3 years ago
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A bird flies due north with a speed of 15 m/s relative to the air. The air moves due west with a speed of 11 m/s relative to the
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4 0
3 years ago
The force F acting on a particle constrained to move along the x - axis is given by the fucntion F ( x ) = a x ( b − c x 2 ) [ a
arlik [135]

Answer:

The equilibrium points include

x₁ = - 1.177

x₂ = 0

x₃ = 1.177

Explanation:

At equilibrium, the sum of forces acting on a body is equal to zero.

F(x) = ax (b − cx²) [a = 8.97, b = 7.83, c = 5.65]

F(x) = (abx - acx³)

= (8.97×7.83)x - (8.97×5.65)x³

F(x) = 70.2351x - 50.6805x³

At equilibrium, F(x) = 0

70.2351x - 50.6805x³ = 0

x(70.2351 - 50.6805x²) = 0

x = 0 or (70.2351 - 50.6805x²) = 0

70.2351 - 50.6805x² = 0

50.6805x² = 70.2351

x² = (70.2351/50.6805)

x² = 1.385840708

x = ± 1.177

So, x = -1.177, 0 and 1.177

x₁ = - 1.177

x₂ = 0

x₃ = 1.177

Hope this Helps!!!

6 0
3 years ago
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