You need to attach the answer choices
Answer with Explanation:
We are given that
A.Mass,m=12 kg
![\theta=53^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D53%5E%7B%5Ccirc%7D)
![\mu_k=0.16](https://tex.z-dn.net/?f=%5Cmu_k%3D0.16)
Speed,v=1.5m/s
Net force in x direction must be zero
![F_{net}=0](https://tex.z-dn.net/?f=F_%7Bnet%7D%3D0)
![Fsin\theta-f=0](https://tex.z-dn.net/?f=Fsin%5Ctheta-f%3D0)
![Fsin\theta=f](https://tex.z-dn.net/?f=Fsin%5Ctheta%3Df)
Net force in y direction
![N-mg-Fcos\theta=0](https://tex.z-dn.net/?f=N-mg-Fcos%5Ctheta%3D0)
![N=mg+Fcos\theta](https://tex.z-dn.net/?f=N%3Dmg%2BFcos%5Ctheta)
![f=\mu_kN=\mu_k(mg+Fcos\theta)](https://tex.z-dn.net/?f=f%3D%5Cmu_kN%3D%5Cmu_k%28mg%2BFcos%5Ctheta%29)
![Fsin\theta=\mu_k(mg+Fcos\theta)](https://tex.z-dn.net/?f=Fsin%5Ctheta%3D%5Cmu_k%28mg%2BFcos%5Ctheta%29)
![Fsin\theta=\mu_kmg+\mu_kFcos\theta](https://tex.z-dn.net/?f=Fsin%5Ctheta%3D%5Cmu_kmg%2B%5Cmu_kFcos%5Ctheta)
![Fsin\theta-\mu_kFcos\theta=\mu_kmg](https://tex.z-dn.net/?f=Fsin%5Ctheta-%5Cmu_kFcos%5Ctheta%3D%5Cmu_kmg)
![F(sin\theta-\mu_kcos\theta)=\mu_kmg](https://tex.z-dn.net/?f=F%28sin%5Ctheta-%5Cmu_kcos%5Ctheta%29%3D%5Cmu_kmg)
![F=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B%5Cmu_kmg%7D%7Bsin%5Ctheta-%5Cmu_kcos%5Ctheta%7D)
Power,P=Fv
![P=\frac{\mu_kmg}{sin\theta-\mu_kcos\theta}v](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B%5Cmu_kmg%7D%7Bsin%5Ctheta-%5Cmu_kcos%5Ctheta%7Dv)
Where ![g=9.8m/s^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fs%5E2)
B.Substitute the values
![P=\frac{0.16\times 12\times 9.8}{sin53-0.16cos53}\times 1.5](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B0.16%5Ctimes%2012%5Ctimes%209.8%7D%7Bsin53-0.16cos53%7D%5Ctimes%201.5)
![P=40.17W](https://tex.z-dn.net/?f=P%3D40.17W)
Answer:
final velocity will be44.72m/s
Explanation:
HEIGHT=h=100m
vi=0m/s
vf=?
g=10m/s²
by using third equation of motion for bodies under gravity
2gh=(vf)²-(vi)²
evaluating the formula
2(10m/s²)(100m)=vf²-(0m/s)²
2000m²/s²=vf²
√2000m²/s²=√vf²
44.72m/s=vf
29.213 cm3
First, calculate the mass of the water used. You do this by subtracting the original mass of the flask from the combined mass of the water and flask, giving:60.735 g - 31.601 g = 29.134 g
So we now know we have 29.134 g of water. To calculate the volume of the flask, simply divide by the density of the water, giving:29.134 g / (0.9973 g/cm3) = 29.213 cm3