Answer:
F = 479.21 N
Explanation:
given,
initial velocity = 0 m/s
final velocity = 16.7 m/s
time taken = 20.7 s
combined mass of the boat and trailer = 594 kg
tension in the hitch = ?
using equation of motion
v = u + a t
16.7 = 0 + a × 20.7
a = 0.807 m/s²
Force = mass × acceleration
F = 594 × 0.807
F = 479.21 N
Hence, the tension in the hitch that connects the trailer to the car is F = 479.21 N
Answer:
b is the answer tennis ball
Answer:
2.5 m/s
Explanation:
Mechanical energy is the sum of the potential and kinetic energy.
E = PE + KE
E = mgh + ½mv²
172.1 J = (7.26 kg) (9.8 m/s²) (2.1 m) + ½ (7.26 kg) v²
v = 2.5 m/s
Answer:
38 cm from q1(right)
Explanation:
Given, q1 = 3q2 , r = 60cm = 0.6 m
Let that point be situated at a distance of 'x' m from q1.
Electric field must be same from both sides to be in equilibrium(where EF is 0).
=> k q1/x² = k q2/(0.6 - x)²
=> q1(0.6 - x)² = q2(x)²
=> 3q2(0.6 - x)² = q2(x)²
=> 3(0.6 - x)² = x²
=> √3(0.6 - x) = ± x
=> 0.6√3 = x(1 + √3)
=> 1.03/2.73 = x
≈ 0.38 m = 38 cm = x
<em>weight = (mass) x (gravity)</em>
Weight = (5.00 kg) x (9.81 m/s²)
weight = (5.00 x 9.81) (kg-m/s²)
<em>Weight = 49.05 Newton</em>
