Answer: There are 18 electrons accounted for in the noble gas of the shorthand electron configuration. For the outermost electrons, there are 0 electrons in the 4s orbital and 3 electrons in the 3d orbitals.
Explanation:
Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.
The electrons are filled according to Afbau's rule in order of increasing energies and thus the electronic configuration for Manganese with 25 electrons is :
![Mn^{4+}:21:[Ar]3d^3](https://tex.z-dn.net/?f=Mn%5E%7B4%2B%7D%3A21%3A%5BAr%5D3d%5E3)
The nearest noble gas is Argon with 18 electrons.
There are 18 electrons accounted for in the noble gas of the shorthand electron configuration. For the outermost electrons, there are 0 electrons in the 4s orbital and 3 electrons in the 3d orbitals.
Answer:
Higher molar mass compounds will be less soluble than lower molar mass molecules of the same type.
Explanation:
Bigger Mass = slower/less soluble
Small Mass = faster/more soluble
Answer:
0.4589J/g°C
Explanation:
Heat energy = 1050J
Mass of iron = 220.0g
Initial temperature (T1) = 10°C
Final temperature (T2) = 20.4°C
Heat energy = mc∇T
Q = mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity of the substance
∇T = change in temperature = T2 - T1
Q = m×c×(T2 - T1)
1050 = 220 × c ×(20.4 - 10)
1050 = 220c × (10.4)
1050 = 2288c
c = 1050 / 2288
C = 0.4589J/g°C
The specific heat capacity of iron is 0.4589J/g°C
Answer:
emitted i think
Explanation:
To determine the type of radiation (alpha, beta or gamma), first determine the background count rate, then the source count rate with no absorber. Next, place a sheet of paper between the source and the monitor. If the counts are significantly reduced, the source emits alpha particles.
Answer:
The molarity of the final solution is 1.7 M
Explanation:
The parameters given are;
First solution = 400 ml of 1.25 M
Second solution = 300 ml of 2.30 M
Therefore, we have;
First solution contains 400/1000 * 1.25 moles = 0.5 moles of the substance
Second solution contains 300/1000 * 2.30 moles = 0.69 moles of the
Hence the sum of the two solutions contains 0.5 + 0.69 = 1.19 moles of the substance
The volume of the sum of the two solutions = 400 ml + 300 ml = 700 ml
Hence we have the concentration of the final solution presented as follows;
700 ml contains 1.19 moles of the substance
Therefore;
1000 ml will contain 1000/700 * 1.19 = 1.7 moles
The molarity of the final solution = The number of moles per 1000 ml = 1.7 M.
