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g100num [7]
3 years ago
10

Is this True or false?

Chemistry
2 answers:
kherson [118]3 years ago
7 0

Answer:

true

Explanation:

11Alexandr11 [23.1K]3 years ago
7 0

Answer:

true AND SOMETHING HAPPENDED TO MI OTHER ACCOUNT

Explanation:

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How does oxidation differ from reduction
Dima020 [189]

Answer:

See the explanation below, please.

Explanation:

In redox reactions (oxide reduction) the transfer of electrons between compounds occurs.

 In oxidation, electrons are lost (positive charge increases). Example:

Mg ---> Mg2 + + 2 e- (passes from Mg ° to Mg 2+)

On the other hand in the reduction, electrons are gained (negative charge increases or the positive one increases). Example:

Cl2 + 2e- ---> 2 Cl- + 2 e- (passes from Cl ° to Cl-)

6 0
3 years ago
How are energy and work related? A. Energy is the force needed to do work B. Work times energy is force C. Energy is the capacit
Svetllana [295]

Answer:

I believe the answer is A

Explanation:

Work and energy are related because when you work, you cause displacement in the object you are exerting upon. While this happens, you transfer energy between the systems. Both work and energy share the same SI unit, called the joule.

4 0
3 years ago
Read 2 more answers
At 700C (1290F), what is the maximum solubility <br> (a) of Cu in Ag? (<br> b) Of Ag in Cu?
DochEvi [55]

Answer:

(a) 4 %; (b) 5 %

Explanation:

We need a Cu-Ag phase diagram to answer these questions (see diagram). Yours may differ slightly from the one I used.

(a) Cu in Ag

The horizontal red line  at 700 °C cuts the right-hand solvus at about 4 % Ag-96 % Cu.

At this point, copper is in equilibrium with the eutectic.

At 700 °C, the maximum solubility of Cu is about 4 % by mass.

(b) Ag in Cu

The horizontal red line  at 700 °C cuts the left-hand solvus at about 5 % Cu-95 % Ag.

At this point, silver is in equilibrium with the eutectic.

At 700 °C, the maximum solubility of Ag is about 5 % by mass.

3 0
3 years ago
8. A foot describes what characteristic of measurement?
n200080 [17]

Answer:

It describes length of measurement...

6 0
3 years ago
It takes 53.0 J to raise the temperature of an 11.0 g piece of unknown metal from 13.0∘C to 24.2 ∘
jasenka [17]
You need to use q = mc(delta t) 
<span>Solve for c: </span>

<span>c = q / m(delta t) </span>

<span>q = 55.o J </span>
<span>m = 11.0 g </span>
<span>delta t = 24.5 - 13.0 = 11.5 deg C </span>

<span>c = 55 J / 11.0 g)(11.5 C) </span>
<span>c = 0.435 J/ g C</span>
7 0
3 years ago
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