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Flauer [41]
3 years ago
10

What happens when you fumble out of bounds?

Physics
2 answers:
Mice21 [21]3 years ago
6 0
You give the ball to the other team
IrinaK [193]3 years ago
5 0

in football when you fumble out of bounds the last team that the ball hit off it is the other teams ball

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What minimum speed must the block have at the base of the 70 m hill to pass over the pit at the far (right-hand) side of that hi
Drupady [299]

Answer:

initial velocity is v = 4.95 m / s

Explanation:

To solve this exercise we use the projectile launch ratios, when the block leaves the hill its speed is horizontal, let's find the time it takes to fall to the other point.

Initial vertical velocity is zero

          y = y₀ + v_{oy} t - ½ g t²

          y-y₀ = 0 -1/2 g t²

          t = \sqrt{ \frac{ 2(y_o -y)}{g} }

calculate

          t = \sqrt{ \frac{2 ( 70-50)}{9.8} }

          t = 2.02 s

with this time we can substitute in the horizontal displacement equation

          x = v₀ₓ t

          v₀ₓ = x / t

suppose that the distance between the two points is x = 10 m

          v₀ₓ = 10 / 2.02

          v₀ₓ = 4.95 m / s

initial velocity is v = 4.95 m / s

4 0
3 years ago
Find the vector parallel to the resultant of the vector A=i +4j-2k and B=3i-5j+k​
Zinaida [17]

Answer:

2008

Explanation:

2000+3+5======2008

8 0
3 years ago
Read 2 more answers
5 litres of alcohol have a mass of 4kg. calculate the density of alcohol in g/cm.​
Aleks04 [339]

Answer: 0.8 g/cm

Explanation:

p= m/V

= 4 kg/ 5 liter

= 0.8

3 0
3 years ago
Read 2 more answers
A large lightning bolt is observed to have a 19500 A current and move 36 C of charge. What was its duration?
Lynna [10]

Answer:

Its duration is 1.85*10⁻³ s or 1.85 ms

Explanation:

The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).

The intensity of electric current is expressed as:

I=\frac{Q}{t}

where:

I: Intensity expressed in Amps (A)

Q: Electric charge expressed in Coulombs (C)

t: Time expressed in seconds (s)

Being:

  • I= 19500 A
  • Q=36 C
  • t=?

Replacing:

19500 A=\frac{36 C}{t}

Solving:

19500 A*t= 36 C

t=\frac{36 C}{19500 A}

t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)

<u><em>Its duration is 1.85*10⁻³ s or 1.85 ms</em></u>

8 0
3 years ago
According to Coulomb’s Law, what happens to the force when the distance increase between 2 particles?
ohaa [14]

Answer:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, <u>the attraction or repulsion becomes weaker</u>, decreasing to one-fourth of the original value.

Explanation:

Coulomb’s law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton’s law of gravity.

Both gravitational and electric forces decrease with the square of the distance between the objects, and both forces act along a line between them. In Coulomb’s law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. Thus, charge determines how electromagnetism influences the motion of charged objects. Charge is a basic property of matter. Every constituent of matter has an electric charge with a value that can be positive, negative, or zero.

Coulomb's Law says that the force between 2 charges is proportional to the product of the quantities of charge on each and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is F=k\frac{q_{1}q_{2}   }{r^{2} }.

F is the force.

k is the Coulomb's constant (8.987*10^{9} \frac{Nm^{2} }{C^{2} }).

q_{1} is the electric charge of object 1.

q_{2} is the electric charge of object 2.

r is the distance between the two charges.

Electric force is inversely proportional to (r^{2}) instead of (r). As the distance between charges increases, the electric force decreases by a factor of \frac{1}{r^{2} }.

8 0
2 years ago
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