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Vilka [71]
3 years ago
7

The disease that affects our lungs is

Chemistry
2 answers:
dsp733 years ago
6 0

Answer:

Smogging and Vaying.

Explanation:

Not Corona. It's good.

motikmotik3 years ago
4 0

Answer:

Lung cancer

Explanation:

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Electron configuration for be+2
svlad2 [7]

Answer:

atomic number of Be =4

electronic configuration :1s²2s²

but for Be2+ atomic number = 4-2 =2

electronic configuration : 1s²

6 0
3 years ago
What can scientists learn from index fossils?
olga2289 [7]

Answer:

dating and correlating the strata in which it is found

Explanation:

3 0
2 years ago
Quinine is an important type of molecule that is involved in photosynthesis. The transport of electrons mediated by quinone in c
Irina18 [472]

Answer:

The heat of combustion is -25 kJ/g = -2700 kJ/mol.

Explanation:

According to the Law of conservation of energy, the sum of the heat released by the combustion reaction and the heat absorbed by the bomb calorimeter is equal to zero.

Qcomb + Qcal = 0

Qcomb = - Qcal

The heat absorbed by the calorimeter can be calculated with the following expression.

Qcal = C × ΔT

where,

C is the heat capacity of the calorimeter

ΔT is the change in temperature

Then,

Qcomb = - Qcal

Qcomb = - C × ΔT

Qcomb = - 1.56 kJ/°C × 3.2°C = -5.0 kJ

Since this is the heat released when 0.1964 g o quinone burns, the energy of combustion per gram is:

\frac{-5.0kJ}{0.1964g} =-25kJ/g

The molar mass of quinone (C₆H₄O₂) is 108 g/mol. Then, the energy of combustion per mole is:

\frac{-25kJ}{g} .\frac{108g}{1mol} =-2700kJ/mol

6 0
3 years ago
Redox 1/2 reaction Cu(s) + 2 AgC2H3O2(aq) = Cu(C2H3O2)2(aq) + 2 Ag(s)
Anna11 [10]

Explanation:

 Reaction:

              Cu  +     2AgC₂H₃O₂     →    Cu(C₂H₃O₂)₂    +     2Ag

The problem is to split the reaction into oxidation and reduction halves:

 The oxidation half is the sub-reaction that undergoes oxidation

  The reduction half is the one that undergoes reduction:

The ionic equation:

 Cu   +  2Ag⁺   +   2C₂H₃O₂⁻   →   Cu²⁺  +  2C₂H₃O₂⁻   +  2Ag

Oxidation half:

     Cu →  Cu²⁺ + 2e⁻

 

Reduction half:

    2Ag⁺ + 2e⁻ → 2Ag

C₂H₃O₂⁻ is neither oxidized nor reduced in the reaction.

learn more:

Oxidation state brainly.com/question/10017129

#learnwithBrainly

4 0
3 years ago
Consider the balanced chemical equation for the combustion of methane (CH4).
Mrac [35]
<h3>Answer:</h3>

                  89.6 L of O₂

<h3>Solution:</h3>

The balanced chemical equation is as,

                                CH₄  +  2 O₂    →    CO₂  +  2 H₂O

As at STP, one mole of any gas (Ideal gas) occupies exactly 22.4 L of Volume. Therefore, According to equation,

             44 g ( 1 mol) CO₂ is produced by  =  44.8 L (2 mol) of O₂

So,

                  88 g CO₂ will be produced by  = X L of O₂

Solving for X,

                        X = (88 g × 44.8 L) ÷ 44 g

                        X = 89.6 L of O₂

5 0
3 years ago
Read 2 more answers
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