All categories

3 years ago

What is the molecular formula?Write down the molecular formula of the given compounds.

Chemistry

1 answer:

sergeinik [125]3 years ago

6 0

Answer:

A molecular formula consists of the chemical symbols for the constituent elements followed by numeric subscripts describing the number of atoms of each element present in the molecule.

The molecular formula of the given compounds are:

CaSO4
Na₂CO₃
H2O
CO2
KNO3
NH4Cl

You might be interested in

Which regions on the periodic table can adopt positive and negative oxidation numbers?

Dennis_Churaev [7]

<span>The region(s) of the periodic table which are made up of elements that can adopt both positive and negative oxidation numbers are the “non-metal” region. As we can see on the periodic table, the elements situated at the right side of the table have two oxidation states, one positive and the other a negative. </span>

7 0

3 years ago

What is a reason why ethers have low water solubility?

professor190 [17]

Ethers can't form hydrogen bonds with water and so have a low solubility

hope that helps

6 0

4 years ago

Read 2 more answers

What property characterizes a spontaneous redox reaction?

Eva8 [605]

Answer: C

Explanation:

Just took it :)

8 0

3 years ago

Sulfur is right below oxygen in the periodic table, meaning it has similar bonding properties. Like oxygen, sulfur can form a co

slava [35]

Sulfur’s Bohr diagram 1 S^2 2S^2 2P^6 3S^2 3S^4. Like Oxygen, needs 2 electrons on outer ring to become stable.

3 0

3 years ago

It take 38.70cm³ of 1.90m NaoH to neutralize 10.30cm³ of H2so4 in a battery, calculate the molar concentration of H2so4

zlopas [31]

Answer:

$M_{acid}=3.57M$

Explanation:

Hello there!

In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

$2M_{acid}V_{acid}=M_{base}V_{base}$

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

$M_{acid}=\frac{M_{base}V_{base}}{2V_{acid}}$

Thus, we plug in the given data to obtain:

$M_{acid}=\frac{38.70cm^3*1.90M}{2(10.30cm^3)} \\\\M_{acid}=3.57M$

Best regards!

8 0

3 years ago