An observer is standing next to the tracks, watching a train approach. The train travels at 30 m/s and blows its whistle at 8,00
1 answer:
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Answer:
4.156 m/s
Explanation:
See attachment
Answer:
v = 54.2 m / s
Explanation:
Let's use energy conservation for this problem.
Starting point Higher
Em₀ = U = m g h
Final point. Lower
= K = ½ m v²
Em₀ = Em_{f}
m g h = ½ m v²
v² = 2gh
v = √ 2gh
Let's calculate
v = √ (2 9.8 150)
v = 54.2 m / s