Answer:
Option e. Blue/Violet
Explanation:
We know that when white light passes through a diffraction grating it spits into a band of seven colors or spectrum which includes the color in the order VIBGYOR that stands for Violet, Indigo, Blue, Green, Yellow, Orange and Red respectively.
Red light has the longest wavelength and is least scattered whereas Violet light with the shortest wavelength is the one to get most scattered and as we move far from bright spot at the center, there is an increase in the wavelength of light, thus the color that corresponds to the closest one is Violet with the shortest wavelength in the band.
Answer:
Answered
Explanation:
Energy of electron in hydrogen atom is given by
E_n= 
now as becomes large
ΔE= E_n+1 - E_n= 18.6 eV(1/n^2- 1/(n+1)^2)
now, as n increases ΔE_n decreases
in the limit n→∞ , ΔE_n→0. Thus with increase in n, energy level come close to each other.
b) Since, the wavelength of the rays depends upon the energy level hence they too come closer.
c)Near the ionization threshold the energy level of the atoms come closer and the total energy of the electron becomes almost so that it can be easily removed from the orbit.
Answer:
True
Explanation: A professional assessment is the only way to determine the health related fitness. These could include blood work, breathing exercises, ect to make sure the person is able to perform the fitness exercises without compromising their health.
The correct answer for this question is this one:
<span>A snowstorm was predicted in Chicago. The possible upper air temperature, surface temperature, and air pressure of Chicago on that day. Normal atmospheric pressure is 29.9 inches of mercury. </span><em>I'm pretty sure the answer is 40 for upper air, 29 for surface temp, and 30 for air pressure. </em>Hope this helps answer your question and have a nice day ahead.
Answer:
a) 6.26 m/s
b) 7.67 m/s
Explanation:
The potential energy at height h0 is initially ...
PE0 = mgh0
At height h1, the potential energy is ...
PE1 = mgh1
The difference in potential energy is converted to kinetic energy:
PE0 -PE1 = KE1 = (1/2)m(v1)^2
Solving for v1, we have ...
mg(h0 -h1) = (1/2)m(v1)^2
2g(h0 -h1) = (v1)^2
v1 = √(2g(h0 -h1))
__
a) When the body is 1 m high, its speed is ...
v = √(2(9.8)(3 -1)) ≈ 6.26 m/s . . . at 1 m high
__
b) When the body is 0 m high, its speed is ...
v = √(2(9.8)(3 -0)) ≈ 7.67 m/s . . . when it reaches the ground
