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Paha777 [63]
3 years ago
12

How much work is done on a satellite in a circular orbit about earth?

Physics
1 answer:
alexgriva [62]3 years ago
3 0

Answer:

0 J

Explanation:

W = Work done on the satellite in circular orbit about earth by earth

F = Force on gravity on satellite by earth

d = displacement of the satellite

\theta = Angle between the force on gravity and displacement = 90

We know that, Work done is given as

W = F d Cos\theta\\W = F d Cos90\\W = F d (0)\\W = 0 J

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Newton's law of cooling is , where is the temperature of an object, is in hours, is a constant ambient temperature, and is a pos
kirill [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The time taken  is  t  = 6.89 \ hrs

 

Explanation:

From the question we are told that

       The value of  k = 0.15hr^{-1}

       The  the interior temperature is  u(t = 0) =  70 ^oF

         The external temperature is  T  = 11 ^oF

          The required interior temperature is  u_{t} = 32 ^oF

      The newton cooling law is

                      \frac{du}{dt}  =  -k (u -T)

=>                 \frac{du}{u-T}  = - kdt

  Now integrate both sides we have  

                 \int\limits \frac{du}{u-T}  =\int\limits   - kdt

                   ln (u - T) =  -kt + c    

Since c is a constant lnC = c   will also give a constant so

                 ln (u - T) =  -kt + ln C    

       =>       \frac{(u -T)}{C}  =  e^{-kt}

     =>        u = T + Ce^{-kt}  

          substituting value

                  70 = 11 +Ce^{-0* 0.15}

                  C = 59

Hence

        u_t =  11 + 59 e^{-0.15 *t}

       32=  11 + 59 e^{-0.15 *t}

=>     t  =  -\frac{ln(\frac{21}{59} )}{0.15}

         t  = 6.89 \ hrs

 

3 0
2 years ago
How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?
tatyana61 [14]
Missing part in the text of the problem: 
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
Q=m C_s \Delta T
where
m=1.8 g is the mass of the water
C_s = 4.18 J/(g K) is the specific heat capacity of the water
\Delta T=2.5 K is the increase in temperature.

Substituting the data, we find
Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E

We know that each photon carries an energy of
E_1 = hf
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and the number of photons needed is the total energy needed divided by the energy of a single photon:
N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons
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F!!! that is false.
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