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3 years ago

Find 3 solutions to the equation y = −4x −1

Mathematics

1 answer:

agasfer [191]3 years ago

4 0

Answer:

(0,-1)

(1,-5)

(2,-9)

Step-by-step explanation:

y = −4x −1

Let x=0

y = 0-1 = -1 (0,-1)

Let x = 1

y = -4(1) -1 = -4-1 =-5 (1,-5)

Let x = 2

y = -4(2) -1 = -8-1 =-9 (2,-9)

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The answer is 3 1/2 or in decimal form it is 3.5

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3 years ago

Geometry question, any help is appreciated

kodGreya [7K]

Answer:

Hence, the ratios are given by 5:7, 25:49, 125:343.

Step-by-step explanation:

We are given two spheres such that:

Volume of small sphere $V_{s}$ = 250 $yd^{3}$

Volume of large sphere $V_{l}$ = 686 $yd^{3}$ .

Then the ratio of volume = 250 : 686 = 125 : 343.

Since, the volume of a sphere = $\frac{4 \pi \times r^{3}}{3}$ , this gives us that the ratio of the radius = ∛ $V_{s}$ : ∛ $V_{l}$

i.e. The ratio of the radius = ∛125 : ∛343 = 5 : 7.

Further, as the surface area of a sphere = $4 \pi \times r^{2}$ , this gives us that the ratioof surface area = $r_{s} ^{2}$ : $r_{l} ^{2}$

i.e The ratio of the surface area = $5^{2}$ : $7^{2}$ = 25 : 49

So, the ratio of the surface areas = 25 : 49.

Hence, the ratios are given by 5:7, 25:49, 125:343.

4 0

3 years ago

Read 2 more answers

What is the circumference of this circle?

Goryan [66]

Answer:

i believe its 12.56637 but rounded off that will be 12.57

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3 years ago

What is the slope of the line given (1,1) and (0,0)

yaroslaw [1]

The slope of the line passing the points (1, 1) and (0, 0) is 1

<h3>Slope of a line</h3>

The formula for calculating the slope of a line is expressed as

Slope = y2-y1/x2-x1

Given the coordinate points (1, 1) and (0, 0)

Substitute the given coordinate points

Slope = 0-1/0-1

Slope = -1/-1

Slope =1

Hence the slope of the line passing the points (1, 1) and (0, 0) is 1

Learn more on slope of a line here: brainly.com/question/3493733

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2 years ago

What is the area of the shaded region on the graph shown?

Sindrei [870]

Answer:

As Doris Day said: Good morning to you

Answer 27/2

Step-by-step explanation:

$f(x)=-x^3+5x\\F(x)=-\dfrac{x^4}{4} +\dfrac{5x^2}{2} \\F(2)=\dfrac{-16}{4}+\dfrac{20}{2} =6\\\\F(-1)=\dfrac{-1}{4} +\frac{5}{2} =\dfrac{9}{4} \\g(x)=\dfrac{3x^2}{2}+\dfrac{x}{2}-5\\\\G(x)=\dfrac{x^3}{2} +x^2-5x\\\\G(2)=4+1-10=-5\\\\G(-1)=\dfrac{-1}{2} +\dfrac{1}{4} +5=\dfrac{19}{4} \\\\\int\limits^2_{-1} {(f(x)-g(x))} \, dx =F(2)-G(2)-(F(-1)-G(-1))\\\\=11+\dfrac{5}{2} =\dfrac{27}{2}$

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3 years ago