Question

Help meh in this question​

Answer 1

• Radius=r=R_o/2
• angular velocity=w=v_o
• mass=m

We know

$\boxed{\sf K.E=\dfrac{1}{2}mv^2}$

For Rotational motion

$\boxed{\sf v=r\omega}$.

Putting value

$\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m(r\omega)^2$

$\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}mr^2\omega^2$

$\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m\left(\dfrac{R_o}{2}\right)^2v_o^2$

$\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{4}mv_o^2$