Answer:
d. 1.4 m/s
Explanation:
Given;
initial velocity of the `basketball, u = 4.0 m/s
acceleration of the basketball, a = -0.5 m/s² (leftward)
distance the basketball traveled, d = 14 m
the final velocity of the basketball, v = ?
(this final velocity should be less than the initial velocity since the ball is slowing down at a constant rate)
Apply the following the kinematic equation;
v² = u² + 2ad
v² = 4² + 2(-0.5)14
v² = 16 - 14
v² = 2
v = √2
v = 1.41 m/s
Therefore, the final velocity of the basketball is 1.4 m/s.
Answer:Luster aka (A)
Explanation:Because luster is something you learned in science.
IF IT HELPED CAN I HAVE BRAINLIEST PLS!! AND GOOD LUCK <3
To solve this problem, it is necessary to apply the concepts related to the work done by a body when a certain distance is displaced and the conservation of energy when it is consumed in kinetic and potential energy mode in the final and initial state. The energy conservation equation is given by:
Where,
KE = Kinetic Energy (Initial and Final)
PE = Potential Energy (Initial and Final)
And the other hand we have the Work energy theorem given by
Where
W= Work
F = Force
D = displacement,
PART A) Using the conservation of momentum we can find the speed, so
The height at the end is 0m. Then replacing our values
Deleting the mass in both sides,
Re-arrange for find
PART B) Applying the previous Energy Theorem,
Solving for d