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Ivahew [28]
3 years ago
5

Any help would be great! Thank you x Giving brainliest answer xoxo

Physics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

A vacuum would have been created. I hope this helps have a great day

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A person tries to lift each object with a force of 25 N, upward. Which
Vlad1618 [11]

Answer:

Option C. Objects 1 and 3 will not move, and objects 2 and 4 will accelerate

upward.

Explanation:

The following data were obtained from the question:

OBJECT >>>>>>>>> WEIGHT (N)

1 >>>>>>>>>>>>>>>> 35

2 >>>>>>>>>>>>>>>> 23

3 >>>>>>>>>>>>>>>> 26

4 >>>>>>>>>>>>>>>> 18

Force (F) applied = 25 N

From the above, the force applied to each object is 25N. Thus the following can be concluded based on the data given above:

For object 1:

Weight = 35 N

Force applied = 25 N

Thus, the object will not move since the weight of the object is greater than the force applied

For object 2:

Weight = 23 N

Force applied = 25 N

Thus, the object will move since the force applied is greater than the weight of the object.

For object 3:

Weight = 26 N

Force applied = 25 N

Thus, the object will not move since the weight of the object is greater than the force applied.

For object 4:

Weight = 18 N

Force applied = 25 N

Thus, the object will move since the force applied is greater than the weight of the object.

From the above illustrations, Object 1 and 3 will not move, and objects 2 and 4 will accelerate i.e move

4 0
3 years ago
Read 2 more answers
A compressed spring does not have elastic potential energy.
Alexus [3.1K]

Answer:

False

Explanation:

The second you let go its gonna release kinetic energy that's why it's potential

6 0
3 years ago
Identical forces act for the same length of time on two different masses. The change in momentum of the smaller mass is
xenn [34]

Answer:

Equal to change in momentum of larger mass.

Explanation:

We are given that

Two difference  masses .

Force act on both masses  for the same length of time.

We have to find the change in momentum of the smaller mass.

Let M and m are two masses

M>m

We know that

Change in momentum for large mass=F\Delta t

Change in momentum for small mass=F\Delta t

Because Force and length of time are same for both masses .

Hence, the change in momentum of smaller mass is equal to change in momentum of larger mass.

7 0
3 years ago
A tow truck drags a stalled car along a road. The chain makes an angle of 30° with the road and the tension in the chain is 1400
AURORKA [14]

Answer:

The work is done by the truck pulling the car 1 km is 1,212,436 J

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another. When a force is applied, an energy transfer occurs. Then it can be said that work is energy in motion.

So work is one of the forms of energy transmission between bodies. To perform a job, you must exert a force on a body and it moves.

In the International System of Units, work is measured in Joule. A Joule is the work that a constant force of 1 Newton does on a body that moves 1 meter in the same direction and direction as the force. Then, Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:

Work= Force*Distante* cos (θ)

In this case:

  • Force= 1,400 N= 1,400 kg*\frac{m}{s^{2} }
  • Distance= 1 km= 1,000 m
  • θ= Angle that exists between the direction of the force and the direction= 30°

Replacing:

Work= 1,400 N* 1,000 m* cos (30°)

Work= 1,212,435. 565 Joule≅ 1,212,436 J

<u><em> The work is done by the truck pulling the car 1 km is 1,212,436 J</em></u>

7 0
3 years ago
A body moves in a straight line. At time, it's acceleration is given by a = 12t + 1. When t =0, the velocity of the body v is 2
madreJ [45]

Answer:

v = 6t² + t + 2, s = 2t³ + ½ t² + 2t

59 m/s, 64.5 m

Explanation:

a = 12t + 1

v = ∫ a dt

v = 6t² + t + C

At t = 0, v = 2.

2 = 6(0)² + (0) + C

2 = C

Therefore, v = 6t² + t + 2.

s = ∫ v dt

s = 2t³ + ½ t² + 2t + C

At t = 0, s = 0.

0 = 2(0)³ + ½ (0)² + 2(0) + C

0 = C

Therefore, s = 2t³ + ½ t² + 2t.

At t = 3:

v = 6(3)² + (3) + 2 = 59

s = 2(3)³ + ½ (3)² + 2(3) = 64.5

5 0
3 years ago
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