3 years ago

2- A student ran 135 meters in 15 seconds. What was the student's velocity?

Physics

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

9 Brainly hahaha ............huh

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An object is moving with an initial velocity of 19 m/s.It is then subject to a constant acceleration of 2.5 m/s for 15s.How far

bija089 [108]

Answer:

566.3 m

Explanation:

The distance travelled by the object can be found by using the SUVAT equation:

$d=ut+\frac{1}{2}at^2$

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a is the acceleration

For the object in this problem:

u = 19 m/s

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Substituting t = 15 s, we find the distance travelled:

$d=(19)(15)+\frac{1}{2}(2.5)(15)^2=566.3 m$

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