Answer:
v to the right.
Explanation:
<u>If there is no external force on the system, then the velocity of the center of mass is </u><u>constant</u><u>. </u>
The initial velocity of center of mass is v to the right. Therefore, the velocity of the center of mass at any point is v to the right.
Answer:
25.9 m/s
Explanation:
mass of ball, m = 0.145 kg
initial velocity, u = + 32 m/s
It bounce back with the velocity but in opposite direction so final velocity,
v = - v
Impulse, I = - 8.4 Ns
Impulse is defined as the change in momentum
I = m v - mu = m (v - u)
- 8.4 = 0.145 x (- v - 3 2)
- 57.9 = - v - 32
v = 57.9 - 32 = 25.9 m/s
Thus, the final speed of the ball is 25.9 m/s
Answer:
a) 19.4 m/s
b) 19 m/s
Explanation:
a) In the given question,
the potential energy at the initial point = Ui = 0
the potential energy at the final point = Uf = mgh
the kinetic energy at the initial point = Ki = 1/2 mv₀².
the kinetic energy at the final point = Kf = 0
work done by air= Ea= fh = 0.262 N
Now, using the law of conservation of energy
initial energy= final energy
Ki +Ui = Kf + Uf +Ea
1/2 mv₀² + 0 = 0 + mgh + fh
1/2 mv₀² = mgh + fh
h = v₀²/ 2g (1 +f/w)
calculate m
m= w/g = 5.29 /9.8
= 0.54 kg
h = 20 ²/ (2 x9.80) x (1 0.265/5.29)
h = 19.4 m.
b) 1/2 mv² + 2fh = 1/2 mv₀²
Vg = 19 m/s
For E = 200 gpa and i = 65. 0(106) mm4, the slope of end a of the cantilevered beam is mathematically given as
A=0.0048rads
<h3>What is the slope of end a of the cantilevered beam?</h3>
Generally, the equation for the is mathematically given as
Therefore
A=\frac{10+10^2+3^2}{2*240*10^9*65*10^6}+\frac{10+10^3*3}{240*10^9*65*10^{-6}}
A=0.00288+0.00192=0.0048rads
A=0.0048rads
In conclusion, the slope is
A=0.0048rads
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