Notice that each reactant is made up of two elements. To predict the products, all you have to do is interchange the combination of the two reactants while taking note that metal comes first, followed by nonmetals. With that being said, the reaction would be:
CaC₂ + 2 H₂O --> C₂H₂ + Ca(OH)₂
<em>So, the answer is C₂H₂.</em>
The gram-formula mass of citric acid is 3(1)+6(12)+5(1)+16(7)=192 g/mol.
This means that in 13.00 grams of citric acid, there are 13.00/192 = 0.067 moles.
From the equation, we know that for every 1 mole of citric acid that is consumed, 3 moles of carbon dioxide are produced.
This means that there are 3(0.067)=0.203 moles.
Since the gram-formula mass of carbon dioxide is 12+2(16)=44 g/mol, meaning it has a mass of 0.203(44)=8.93 g
Answer:
N = n× l
N = number of entities
n= moles
l = Avogadro's constant = 6.023 × 10^23
3.01 × 10^ 23 = n * 6.023 × 10^23
n = 3.01 × 10^23/6.023 × 10^23
n= 0.5moles
Molar mass = mass/ number of moles
Molar mass = 56
mass = 56 × 0.5
= 28g
Hope this helps.
Answer:
Mass = 182.4 g
Explanation:
Given data:
Number of moles of Al₂O₃ = 3.80 mol
Mass of oxygen required = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Now we will compare the moles of aluminum oxide and oxygen.
Al₂O₃ : O₂
2 : 3
3.80 : 3/2×3.80 = 5.7
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 5.7 mol × 32 g/mol
Mass = 182.4 g
It would be a continuous straight line
