Nitrogen and oxygen are in unpolluted air
Answer is: the volume of an irregular object is 4,00 ml.
<span>Volume is the amount of space the object occupies and can be finded immersing it in water in a container with volume markings and than see how much the level of the container changes (goes up).
</span>V(irregular object) = V(final volume) - V(initial volume).
V(irregular object) = 7,50 ml - 3,50 ml.
V(irregular object) = 4,00 ml.
6840 is the answer hope this help
Answer:
See the answer below.
Explanation:
Fire has three major components:
- Heat
- Smoke
- Gases ( in form of CO, CO2 etc)
If the victim had died as a result of the fire, he/he would have inhaled smoke and hot gases from the fire. These components would have resulted in traces of burns and soot deposition in the trachea and lungs as well as traces of CO in the blood of the victim.
If the analysis of the victim's corpse does not reflect some of the results above, it can be effectively concluded that the victim has been dead before the fire.
<em>The single most important indicator of death by the fire would be the presence of CO in the blood of the victim's corpse. All others might be to a less significant degrees.</em>
Answer:
Explanation:
The nuclear equation from which you have to identify the missing element is:
- ²³⁹₉₄ Pu + ¹₀n → ___ + ¹³⁴₅₄Xe + 3 ¹₀n
The superscripts to the left of each chemical symbol are the mass number of the atoms (number of protons plus neutrons) and the subscripts to the left of the chemical symbols are the atomic numbers of the atoms (number of protons).
Thus, such equation must be read as "an atom of plutonium-239 is bombarded with a neutron and produces one atom of an unkwon element, one atom of xenon-134, and 3 neutrons".
To find the identity of the missing element you must do two balances: mass number and atomic number.
Mass number:
Hence, the mass number of the missing element is 103.
Atomic number:
Hence, the atomic number of the missing element is 40.
In a periodic table you can find that the element with atomic number 40 is zirconium, Zr.
Thus, the identity of the missing isotope is zirconium-103, ¹⁰³₄₀Zr.
And the complete equation is:
- ²³⁹₉₄ Pu + ¹₀n → ¹⁰³₄₀ Zr + ¹³⁴₅₄Xe + 3 ¹₀n
