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ANEK [815]
3 years ago
10

A moving freight car collides with an identical one that is at rest. If momentum is conserved, what happens to the second car af

ter the collision?
Physics
1 answer:
JulijaS [17]3 years ago
8 0
<h2>Answer</h2>

There will be two different possiblites as

May be one is in rest or other move

May be both will be in motion

<h2>Expalanation</h2>

According to Conservation Law of Momentum, when the two objects collide with each other, they transferred their kinetic energy to keep their momentum before or after collisions remain constant. In the present example, one moving car collides with another car which is at rest and has the same weight. There will be two possibilities after the collision as an elastic collision or perfect inelastic collision. In the elastic collision, the one car will adopt the rest position after the collision and transfer it K.E to make the rest car at the movable position. In the perfect inelastic collision, both cars will move after the collision.

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Answer:

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6 0
2 years ago
A person driving her car at 48 km/h approaches an intersection just as the traffic light turns yellow. She knows that the yellow
trasher [3.6K]

Answer:

She must stop the car  before interception, distance traveled 12.66 m

Explanation:

We will take all units to the SI system

Vo = 48Km / h (1000m / 1Km) (1h / 3600s) = 13.33 m / s

V2 = 70 Km / h = 19.44 m / s

We calculate the distance traveled before stopping

X = Vo t + ½ to t²

Time is what it takes traffic light to turn red  is t = 2.0 s

X = 13.33 2 + 1.2 (-7) 2²

X = 12.66 m

It stops car before reaching the traffic light turning to red

Let's analyze what happens if you accelerate, let's calculate the acceleration of the vehicle

     V2 = Vo + a t2

      a = (V2-Vo) / t2

      a = (19.44-13.33) /6.6

      a = 0.926 m / s2

This is the acceleration to try to pass the interception, now let's calculate the distance it travels in the time the traffic light changes from yellow to red (t = 2.0 s)

X = Vo t + ½ to t²

X = 13.33 2 + ½ 0.926 2²

X = 28.58 m

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4 0
3 years ago
A speedboat initially at rest accelerates at 4.0 m/s (squared) for 7.0 s. How far does the speedboat move in 7.0 s?
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2 years ago
What is the average velocity of the particle from rest to 9 seconds?
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7 0
2 years ago
A 100 kg bungee jumper leaps from a bridge. The bungee cord has an un-streched equilibrium length of 10 m, and a spring constant
nika2105 [10]

Answer:

11.78meters

Explanation:

Given data

Mass m = 100kg

Length of cord= 10m

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At the greatest vertical distance, the spring potential energy is equal to the gravitational potential energy

That is

Us=Ug

Us= 1/2kx^2

Ug= mgh

1/2kx^2= mgh

0.5*35*10^2= 100*9.81*h

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Hence the bungee jumper will reach 1.78+10= 11.78meters below the surface of the bridge

6 0
3 years ago
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