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adoni [48]
3 years ago
7

On a cello, the string with the largest linear density (1.58 10-2 kg/m) is the C string. This string produces a fundamental freq

uency of 65.4 Hz and has a length of 0.805 m between the two fixed ends. Find the tension in the string.
Physics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

F=175.2N

Explanation:

The relationship of between fundamental frequency, density of the string, length and tension of the string is:

L=\frac{1}{2f} \sqrt{\frac{F}{\frac{L}{m} } }

where L/m is the linear density.

make F the subject of the formula

F=4L^{2}f^{2}  \frac{L}{m}

substitute the values

F=4*0.805^{2} *65.4^{2} *(1.58*10^{-2} )\\F=175.2N

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The half-life of the radioactive element beryllium-13 is 5 × 10-10 seconds, and half-life of the radioactive element beryllium-1
telo118 [61]
<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>

Explanation:

The half-life h of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.

In this case, we are given the half life of two elements:

beryllium-13: h_{B-13}=5(10)^{-10}s=0.0000000005s

beryllium-15: h_{B-15}=2(10)^{-7}s=0.0000002s

As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?

We can find it out by the following expression:

h_{B-15}=X.h_{B-13}

Where X is the amount we want to find:

X=\frac{h_{B-15}}{h_{B-13}}

X=\frac{2(10)^{-7}s}{5(10)^{-10}s}

Finally:

X=400

Therefore:

The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.

8 0
2 years ago
A charge of -3.02 μC is fixed in place. From a horizontal distance of 0.0377 m, a particle of mass 9.43 x 10^-3 kg and charge -9
Andreyy89

Answer:

d = 0.0306 m

Explanation:

Here we know that for the given system of charge we have no loss of energy as there is no friction force on it

So we will have

U + K = constant

\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2

now we know when particle will reach the closest distance then due to electrostatic repulsion the speed will become zero.

So we have

\frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{0.0377} + \frac{1}{2}(9.43 \times 10^{-3})(80.4)^2 = \frac{(9 \times 10^9)(3.02 \mu C)(9.78 \mu C)}{r} + 0

7.05 + 30.5 = \frac{0.266}{r}

r = 7.08 \times 10^{-3} m

so distance moved by the particle is given as

d = r_1 - r_2

d = 0.0377 - 0.00708

d = 0.0306 m

6 0
3 years ago
A student weighing 120 lbs climbs a 12 ft flight of stairs in 9 seconds. how much power did the student create?
Alex Ar [27]
Power can be calculate through the equation,
                        Power = Force x velocity

It should be noted that velocity is calculated by dividing displacement by time. Thus, from the given in this item we can calculate for the power. 
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7 0
3 years ago
If the density of a substance is 5g/cm3 and the volume is 10cm3,<br> determine the mass.
vaieri [72.5K]

Answer:

(5g/cm³)*(10cm³) = 50g

Explanation:

This is just a conversion formula. Easy to find using dimensional analysis.

(5g/cm³)*(10cm³) = 50g

6 0
2 years ago
Read 2 more answers
What is a chemical substance that cannot be broken down into another substance?
Tema [17]
The answer is C. Elements 

Elements cannot be broken down int simpler substances even by chemical means
6 0
3 years ago
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