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adoni [48]
3 years ago
7

On a cello, the string with the largest linear density (1.58 10-2 kg/m) is the C string. This string produces a fundamental freq

uency of 65.4 Hz and has a length of 0.805 m between the two fixed ends. Find the tension in the string.
Physics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

F=175.2N

Explanation:

The relationship of between fundamental frequency, density of the string, length and tension of the string is:

L=\frac{1}{2f} \sqrt{\frac{F}{\frac{L}{m} } }

where L/m is the linear density.

make F the subject of the formula

F=4L^{2}f^{2}  \frac{L}{m}

substitute the values

F=4*0.805^{2} *65.4^{2} *(1.58*10^{-2} )\\F=175.2N

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Two rocks are at the top of a building. Rock 1 is dropped from rest while Rock 2 is thrown horizontaly at a velocity of 5 ms.
LuckyWell [14K]

Answer:

I'm pretty sure the answer is 0 m/s²

Explanation:

The horizontal velocity of the second rock is 5 m/s, so if we pretend air resistance doesn't exist, it will maintain that horizontal velocity, meaning that there is no horizontal acceleration.

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3 years ago
3) A 15.0kg cannonball is ascending after being launched. Neglect drag.
WINSTONCH [101]

Answer:

c

Explanation:

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The unit of electric potential or electromotive force is the
Natalka [10]
That would be called VOLT
4 0
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An automobile having a mass of 1,000 kg is driven into a brick wall in a safety test. The bumper behaves like a spring with cons
vlada-n [284]

Answer:

v=2.02\frac{m}{s}

Explanation:

Assuming no energy lost, according to the law of conservation of energy, the kinetic energy of the automobile becomes potential energy after the crash:

K=U\\\frac{mv^2}{2}=\frac{kx^2}{2}

Here m is the automobile's mass, v is the speed of the car before impact, k is the "bumper" constant and x is the compression of the bumper due to the collision. Solving for v:

v=x\sqrt\frac{k}{m}\\v=2.63*10^{-2}m\sqrt{\frac{5.9*10^6\frac{N}{m}}{10^3kg}}\\v=2.02\frac{m}{s}

8 0
3 years ago
an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall, what is the height of
Hitman42 [59]

The height of the object will be -5.19 cm

A concave mirror's reflecting surface curves inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.

Given an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall

So let,

v =  Image distance from the mirror = -33.5 cm

u = object distance from the mirror (concave) = 24 cm

hi = Image height = 7.25 cm

h = height of the object = ?

Using below formula to find height of the object

-v/u = hi/h

Putting all value in the formula we get

-(-33.5)/(-24) = 7.25/h

h = -5.19 cm

Therefore the height of the object will be -5.19 cm

Learn more about Concave mirror here:

brainly.com/question/3727024

#SPJ10

3 0
2 years ago
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