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Aleks04 [339]
3 years ago
15

6) A ball free falls from the top of the roof for 5 seconds. How far did it fall? What is its final

Physics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

distance fallen = 122.5 m

speed = 49 m/s

Explanation:

Δd = vi*t - 0.5at^2

Δd = 0 - 0.5(9.8)(5^2)

Δd = -122.5 (i.e. 122.5m down)

a = (vf - vi) / t

9.8 = (vf - 0) / 5

vf = 49

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Since the ball was not moving before it let Aiden's hand, the formula used to calculate the acceleration is
a =  \frac{v}{t}
, where a is acceleration, v is velocity and t is the time. We put them in the formula and get
a =  \frac{49}{0.1}  \\ a =  \frac{490}{1}  \\ a = 490
The acceleration is 490 m/s^2
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2 years ago
1.   A car travels along a straight road to the east for 100 meters in 4 seconds, then go the west for 50 meters in 1 second.
Alla [95]

Answer:

a.Distance = 150 m

b. Displacement = 50 m

Time lapsed = 5 seconds

Explanation:

a. Distance is the change in the position of an object.

The distance covered by the car = 100 + 50

                                                   = 150 m

b. Since displacement is a vector quantity,

Displacement of the car = 100 - 50

                                        = 50 m due east

c. Time elapsed is the time taken for the motion of the car starting from when its starts to when it stops.

Thus, the time elapsed = 4 + 1

                        = 5 seconds

4 0
3 years ago
A cue ball, moving with 9.0 N·s of momentum strikes the nine-ball at rest. The nine-ball moves off with 2.0 N·s in the original
lisov135 [29]

Answer:

P = 7.28 N.s

Explanation:

given,

initial momentum of cue ball in x- direction,P₁ = 9 N.s

momentum of nine ball in  x-  direction, P₂ = 2 N.s

momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s

momentum of the cue after collision = ?

using conservation of momentum

in x- direction

P₁ + p = x  + P₂

p is the initial momentum of the nine balls which is equal to zero.

9 + 0  = x  + 2

x = 7 N.s

momentum in x-direction.

equating along y-direction

P'₁ + p = y + P'₂

0 + 0 = y + 2

y = -2 N.s

the momentum of the cue ball after collision is equal to resultant of the momentum .

P = \sqrt{x^2+y^2}

P = \sqrt{7^2+(-2)^2}

      P = 7.28 N.s

the momentum of the cue ball after collision is equal to P = 7.28 N.s

7 0
3 years ago
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