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lana [24]
3 years ago
9

Define physical and chemical properties, provide three examples of each, discuss their reversibility, and explain the fundamenta

l differences between them.
Chemistry
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

Physical properties are defined as the properties which can be observed without changing its chemical composition. For example: color, volume, and molecular weight. Chemical properties are defined as the properties which can be observed only after changing chemical identity of the substance.

<h3>Mark me a brainlist</h3>

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How many moles of gas are in a room with a volume of 85.0 L? A light bulb in the same room at the same temperature and pressure
Oduvanchick [21]

Answer: A light bulb in the same room at the same temperature.

Explanation: Yw, BYE!!!

7 0
3 years ago
In this reaction: Mg (s) + I₂ (s) → MgI₂ (s), if 10.0 g of Mg reacts with 60.0 g of I₂, and 53.88 g of MgI₂ form, what is the pe
ad-work [718]

We know the law of conservation of mass

  • It states that mass is neither formed nor destroyed in any chemical reaction.
  • Mass of reactants=Mass of products.

Here

  • Mg and I_2 are reactants
  • MgI_2 is product with some yield.
  • Mass of reactants=10+60.0=70.0g
  • Mass of MgI_2=53.88g
  • Mass of yield=Product-MgI_2=70-53.88=16.12g

Lets find the percentage

\\ \tt\hookrightarrow \dfrac{Mass\:of\:yield}{Total\:mass}\times 100

\\ \tt\hookrightarrow \dfrac{16.12}{70}\times 100

\\ \tt\hookrightarrow 0.23028(010)=23.028\%

6 0
2 years ago
Read 2 more answers
What is the product of radioactive decay He called?
Zinaida [17]

Answer:

Alpha, Beta, and Gamma particles according to ability to penetrate matter.

Explanation:

  • Alpha represent the largest particle which penetrates the least with a positive charge,
  • Beta particles carry a negative charge, and
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3 0
3 years ago
If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
Evgesh-ka [11]

Answer:

E. None of these

Explanation:

We know, By GAS laws,

PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

\frac{P1V1}{RT1} = \frac{P2V2}{RT2}

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

\frac{1*20}{R*10} = \frac{10*V2}{R*100}

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

\frac{1*20*100}{10*10} = V2

∴ V2 = \frac{2000}{100}

∴ V2 = 20mL

3 0
2 years ago
5. Select the answer for both questions ​
salantis [7]

Answer:

engey

Explanation:

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3 years ago
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