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Allisa [31]
3 years ago
5

How can a high school student have more momentum than a truck

Physics
1 answer:
morpeh [17]3 years ago
6 0

Answer:

When truck is at rest while student is under motion

Explanation:

Since it is obvious that the mass of a truck is more than that of a student, we know that momentum is a product of mass and velocity

P=mv where m represent mass, v is velocity. When the student has more speed than that of truck, he exerts more momentum. The only way a student can exert more momentum is by having more speed while the truck is at rest. In such case, the momentum of truck will be zero while momentum of student will have a value

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Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50 μm2. Convert this
Paladinen [302]
1 m = 1 000 000 ym

converted other way we can say that:

1 ym = 10^{-6} m

Now, since we have ym^2 which is ym*ym which means:
1 ym^2 = (10^{-6}) ^2  =  10^{-12} m

we have 1,5 ym^2 which means that answer is:
1.5* 10^{-12} m
8 0
4 years ago
8750 J of heat are applied to a piece of aluminium causing a 56C increase in its
vitfil [10]

Answer:146.8983 grams

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3 years ago
A 0.4000 kg sample of methanol at 16.0ºC is mixed with 0.4000 kg of water at 85.0ºC. Assuming no heat loss to the surroundings,
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Answer:

T_finalmix = 59.5 [°C].

Explanation:

In order to solve this problem, a thermal balance must be performed, where the heat is transferred from water to methanol, at the end the temperature of the water and methanol must be equal once the thermal balance is achieved.

Q_{water}=Q_{methanol}

where:

Q_{water}=m_{water}*Cp_{water}*(T_{waterinitial}-T_{final})

mwater = mass of the water = 0.4 [kg]

Cp_water = specific heat of the water = 4180 [J/kg*°C]

T_waterinitial = initial temperature of the water = 85 [°C]

T_finalmix = final temperature of the mix [°C]

Q_{methanol}=m_{methanol}*Cp_{methanol}*(T_{final}-T_{initialmethanol})

Now replacing:

0.4*4180*(85-T_{final})=0.4*2450*(T_{final}-16)\\142120-1672*T_{final}=980*T_{final}-15680\\157800=2652*T_{final}\\T_{final}=59.5[C]

4 0
3 years ago
A train car with mass m1 = 515 kg is moving to the right with a speed of v1 = 7.5 m/s and collides with a second train car. The
Anna [14]

Answer:

For the first situation, we first need to find the mass of the second train car.

In order to do that, we apply the conservation of the amount of movement:

515*7.5+m2*0=(m1+m2)*4.8

and we have as a result:

m2 = 289.6875

For the second situation, also we will apply the conservation of the amount of movement:

515*7.5-289.6875*6 = (515+289.6875)*V

and we have as a result:

V = 2.64 (it is moving to the right)

6 0
3 years ago
Which particle rarely interacts with matter?
Marysya12 [62]
D. Neutrino
Neutrinos are particles that rarely interact with matter.
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