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VashaNatasha [74]
3 years ago
13

Someone please help me!! See PDF to help

Physics
2 answers:
vaieri [72.5K]3 years ago
8 0

Explanation:

They are invisible is the answer.

Mama L [17]3 years ago
5 0

Answer:

They are invisible!

Explanation:

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If you and your friend EACH apply 55N of force pushing against a wall for 10 minutes. How much work did you do? ​
iris [78.8K]

Answer:

0 Joules

Explanation:

If you are pushing against a wall, the wall is not moving, so no work is being done.

8 0
3 years ago
1000 tiene 3 ceros cuantos lugares crees que se tenga que recorrer el punto decimal​
Neporo4naja [7]

Answer:

Explanation:

Scientific notation is very useful for very large and small quantities, it is based on placing an integer and respecting the decimal figures multiplied by a factor so that the measurement is not altered.

in the example of this exercise we must run the decimal point

        1000 = 1,000 103³

TRASLATE  

La notación científica es muy útil para magnitudes muy grandes y pequeñas, se basa en colocar un entero y el respeto las cifras en decimales multiplicado por un factor para que no se altere la medida.

en el ejemplo de este ejercicio  debemos corre la punto decimal

        1000 = 1,000 10³

4 0
3 years ago
The next two questions refer to this situation: A rectangular loop with sides of length a= 1.00 cm and b= 2.70 cm is placed near
alisha [4.7K]

Answer:

a) 1.007 * 10^{-7} V.m , into the page

b) -5.39 * 10^{-8} V, counterclockwise

Explanation:

a) d\Phi = B.dA\\\\B_r = \frac{\mu_0I}{2\pi r}\\\\dA = b.dr\\\\\Phi = \int\limits^b_a {B.dA} = \int\limits^{a+d}_d {\frac{\mu_0I}{2\pi r}.b.dr} =\frac{\mu_0I}{2\pi }.b.ln(\frac{a+d}{d} )\\

At t = 2.90, I = 3.62 + 1.49 * (2.90)^2 = 16.15 A

\Phi = \frac{4\pi * 10^{-7}*16.15*0.027}{2\pi} ln(1.46/0.46) = 1.007 * 10^{-7} V.m

Direction is into the page.

b) emf = -d\Phi/dt = -\frac{\mu_0}{2\pi }.b.ln(\frac{a+d}{d}).(2.98t)= \\=-\frac{4\pi * 10^{-7}*0.027}{2\pi} ln(1.46/0.46)*2.98*2.90= -5.39 * 10^{-8} V

Direction is counterclockwise.

8 0
3 years ago
Answer the assignment questions using the World Geology map in this lesson and/or the earth's lithospheric plates map in the ass
Advocard [28]
3 I think sorry if wrong
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3 years ago
You are using a constant force to speed up a toy car from an initial speed of 6.5 m/s
Pachacha [2.7K]

By the work-energy theorem, the total work done on the car is equal to the change in its kinetic energy:

<em>W</em> = ∆<em>K</em>

<em>W</em> = 1/2 (0.34 kg) (22.9 m/s)² - 1/2 (0.34 kg) (6.5 m/s)²

<em>W</em> ≈ 82 J

7 0
3 years ago
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