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alexandr1967 [171]
3 years ago
12

What is the function of a hypothesis in the scientific inquiry process

Physics
1 answer:
iris [78.8K]3 years ago
8 0
You can use them by analyzing the way you can solve it.
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If two parallel conductors are both free to move and are carrying current in the same direction, what would happen if the curren
pishuonlain [190]

The wires would remain attracted to each other.

Option D.

Explanation:

It is known that magnetic flux will be generated in conductors with varying emf. So when current is flowing in two parallel conductors, the magnetic flux will be generated in those wires. If the current is flowing in same direction in both the wires, then the magnetic flux will be generated towards inside and outside the wires. Thus, the wire will get attracted to each other till the time the current is flowing in the same direction in both the wires. So if the current flow in each wire was reversed at the same time, then the wire would remain attracted to each other.

8 0
3 years ago
A stone is thrown vertically upwards with an intinal velocity of 20 m/sec . find the maximum height it reaches and the time by i
serious [3.7K]

Answer:

Maximum height is20m and time taken will be 2second

Explanation:

vi=20m/s

vf=0m/s

g=10m/s^2

Using third equation for objects falling freely

2gh=(vf)^2-(vi)^2

Putting values

2(10m/s^2)h=(0m/s)^2-(20m/s)^2

20h=400m

h=20m

Now we have to find the time

Using first equation of motion for objects falling down freely

vf=vi+at

substituting the equation

(vf-vi)/g=t

(0-20)/10=t

t=2second

4 0
3 years ago
A proton is moved from the negative to the positive plate of a parallel-plate arrangement. The plates are 1.50 cm apart, and the
Nana76 [90]

(a) The proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

(b) The potential difference between the negative plate and a point midway between the plates is 11.25 V.

(c) The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

<h3>Potential energy of the proton</h3>

U = qΔV

where;

  • q is charge of the proton
  • ΔV is potential difference

U = q(Ed)

U = (1.6 x 10⁻¹⁹)(1500 x 1.5 x 10⁻²)

U = 3.6 x 10⁻¹⁸ J

<h3>Potential difference between the negative plate and a point midway</h3>

ΔV = E(0.5d)

ΔV = 0.5Ed

ΔV = 0.5 (1500)(1.5 x 10⁻²)

ΔV = 11.25 V

<h3>Speed of the proton </h3>

U = ¹/₂mv²

U = mv²

v² = 2U/m

where;

  • m is mass of proton = 1.67 x 10⁻²⁷ kg

v² = (2 x 3.6 x 10⁻¹⁸) / ( 1.67 x 10⁻²⁷)

v² = 4.311 x 10⁹

v = √(4.311 x 10⁹)

v = 6.57 x 10⁴ m/s

Thus, the proton’s potential energy change is 3.6 x 10⁻¹⁸ J.

The potential difference between the negative plate and a point midway between the plates is 11.25 V.

The speed of the proton just before it hits the negative plate is 6.57 x 10⁴ m/s.

Learn more about potential difference here: brainly.com/question/24142403

#SPJ1

4 0
2 years ago
The physical structure of the earth’s rock is changed by _____.
PSYCHO15rus [73]
It could be stress or strain
4 0
4 years ago
Read 2 more answers
Explain the runaway refrigerator effect and the role it may have played in the evolution of Mars.
Fiesta28 [93]

Answer:

Explained

Explanation:

The runway refrigerator effect and the role it would have played in the evolution of Mars can be summarized as follows

The weak gravity of Mars does not allow it have a gaseous atmosphere over it. The thin atmosphere would have lead to lower temperature on mars.In in turn would have lead to freezing of gases thus lowering the temperature further. The thinner atmosphere and colder temperature would lead to loss of most water in the planet.

6 0
3 years ago
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