Answer:
The magnitude of the force on an electron is 0.069 N.
Explanation:
Given that,
Distance between 1.70 A from the plutonium nucleus, 
The number of electron in iron nucleus is +26e.
To find,
The magnitude of the force between an iron nucleus.
Solution,
Total charge in the plutonium nucleus is,
. The electric force between charges is given by :


F = 0.069 N
So, the magnitude of the force on an electron is 0.069 N. Hence, this is the required solution.
Answer:
total work is = 52450 J
Explanation:
given data
mass = 5000-lb
density = 10 lb/ft
height = 50 ft
solution
as we will treat here cable and ball are separate
and
here work need to lift cable is
w = (10Δy )(9.8 y ) j
and
now summing all segment of cable
so passing limit Δy to 0
so total work need
=
=
= 2450J
so lifting 5000 lb wrcking 50 m required additional 5000 + 2450
so total work is = 52450 J
Answer:
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Answer:
positive attitude lets you relax, remember, focus and absorb information as you learn. You're ready to welcome new experiences and recognize many different kinds of learning opportunities. And when you can see opportunities, hope increases.