1(N2) + 3(H2) --> 2(NH3)
The number in front of the molecules are the mole number
3.5*1(N2) + 3.5*3(H2) --> 3.5*2(NH3)
3.5(N2) + 10.5(H2) --> 7(NH3)
It would produce 7 miles of NH3
Answer:
Honestly, I'm not even sure what the incorrect student was trying to do. The correct answer is:
( ) = the number of elements
(1)N2 and (3)H2
I think the student added the N2 and H2 to "balance" the chemical equation when instead they should have tried the balance the equation by making sure the atoms on the reactant side are equal to the atoms on the product side. You do this by multiplying the atoms on the reactant side until they equal the product side (not by adding them, as the student did).
Solution :
Compound Ksp


FeS 


Ksp of
and both compounds dissociate the same way. Hence
is more soluble than 
is less soluble than 
It is not possible to determine CD -
is more or less soluble than
as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.
can be directly compared with PbS, 



100
1-s s 2s
Ksp = ![[A2+][B-]^2 = s \times (2s)^2 = 4s^3](https://tex.z-dn.net/?f=%5BA2%2B%5D%5BB-%5D%5E2%20%3D%20s%20%5Ctimes%20%282s%29%5E2%20%3D%204s%5E3)
Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
For Silver Chloride


1 0 0
1 - s s s
Ksp ![$=[A^{x+}][B^{x-}]=s \times s = s^2$](https://tex.z-dn.net/?f=%24%3D%5BA%5E%7Bx%2B%7D%5D%5BB%5E%7Bx-%7D%5D%3Ds%20%5Ctimes%20s%20%3D%20s%5E2%24)
Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
The answer for this one is a