The equation for the nuclear fusion reaction is,
4 ¹₁H → ₂⁴He + 2 ₁⁰e
Calculation of mass defect,
Δm = [mass of products - mass of reactants]
= 4(1.00782) - [4.00260 + 2(0.00054858)]
= 0.0275828 g/mole
Given that,
Mass of Hydrogen-1 = 2.58 g
The no. of moles of ₁¹H = 2.58 g / 1.00782 = 2.56 moles
Therefore, the mass defect for 2.58 g of ₁¹H is,
= 2.56 moles * (0.0275828 g / 4) = 0.01765 x 10⁻³ kg
Energy for (0.01765 x 10⁻³ kg) is,
= (0.01765 x 10⁻³ kg) (3.0 x 10⁸)² = 1.59 x 10¹² J
Why, Hello There! The 3 Kinds of rocks that are apart of the rock cycle is...
1.S<span>edimentary
2.M</span><span>etamorphic
And
</span><span>
3.Igneous
Hoped i helped!
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P1V1 = P2V2
1.2ATM*(.7 L) = V2 * .95L
V2 = 0.884 Liters or 884.21 ml
1 yd = 36 in and 1 kg = 1000 g
Hope this helps!
<span>A- solute is the answer you were looking for
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