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4 years ago

Which considerations are used to calculate a windchill factor? Select two options.

Physics

2 answers:

vlada-n [284]4 years ago

7 0

Wind speed and air temperature are used to calculate a windchill factor.

Explanation:

Wind-chill factor is the reduction of body temperature due to the passing flow of lower-temperature air.

The air temperature value is always higher than the wind chill numbers. the heat index will be used if the apparent temperature is higher than the air temperature.So, Wind speed and air temperature are mainly used to calculate a windchill factor.

There are many ways, the surface loses its heat through conduction, evaporation,radiation, and convection.The rate of convection depends on the difference in temperature between the surface and the fluid surrounding the surface and the velocity of that fluid with respect to the surface. The air around the warm surface will be heated, an insulating layer of warm air forms against the surface.The layer becomes a boundary between two. As the wind speed is high the surface cools down rapidly.

mamaluj [8]4 years ago

6 0

Answer:

wind speed and air temperature

Explanation:

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A 7.75-l flask contains 0.482 g of hydrogen gas and 4.98 g of oxygen gas at 65°c. What is the partial pressure of oxygen in the

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Answer:

0.558 atm

Explanation:

We must first consider that both gases behaves like ideal gases, so we can use the following formula: PV=nRT

Then, we should consider that, whithin a mixture of gases, the total pressure is the sum of the partial pressure of each gas:

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4 years ago

a 45 kg sled is pulled down a sidewalk with a horizontal rope. a force of 625 N is applied and the coefficient of kinetic fricti

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3 years ago

If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.2 ss , how far do you travel during this ina

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Answer: 55m

Explanation:

Given the following :

Driving speed = 90km/hr

Inattentive period (time) = 2.2s

Distance during inattentive period =

(driving speed * time)

Converting driving speed from km/hr to m/s

1000m = 1km

3600s = 1hour

Therefore,

90km/hr = (90 * 1000) / 3600

90km/hr = (90000)/ 3600 = 25m/s

Therefore ;

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(driving speed * time)

Distance during inattentive period = (25m/s × 2.2s) = 55m

Distance traveled during inattentive period is 55m

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3 years ago