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3 years ago

Explan respinsible behaviour inthe computer

Chemistry

2 answers:

const2013 [10]3 years ago

8 0

Answer:

This can be done with Python. If you learn machine learning, you can use python to automate your computers to do things.

<h3>2 things you can do with a computer with python + more</h3>

Make and run games or applications easier

Your computer can send or tell you messages at a given time.

I hope this answers you. If not, I may change something accordingly.

hichkok12 [17]3 years ago

5 0

How to behave in computer labs: - the computer labs are solely meant for the use of computers. Smoking, eating and drinking in the computer labs is strictly prohibited. Talking should be restricted to a minimum with consideration to the other users.

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3 years ago

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3 years ago

P + O2 → P4O10 balance the equation

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3 years ago

How many grams of material is lost in the aqueous phase if two extractions are carried out on 100 mL of a 5% (m/v) aqueous solut

san4es73 [151]

Answer:

4.94g of material

Explanation:

Partition coefficient (Kp) of a substance is defined as the ratio between concentration of organic solution and aqueous solution, that is:

Kp = 8 = Concentration in Ethyl acetate / Concentration in water

100mL of a 5% solution contains 5g of material in 100mL of water. Thus:

8 = X / 100mL / (5g-X) / 100mL

Where X is the amount of material in grams that comes to the organic phase.

8 = X / 100mL / (5g-X) / 100mL

8 = 100X / (500-100X)

4000 - 800X = 100X

4000 = 900X

4.44g = X

Thus, in the first extraction you will lost 4.44g of material from the aqueous phase.

And will remain 5g-4.44g = 0.56g.

In the second extraction:

8 = X / 100mL / (0.56g-X) / 100mL

8 = 100X / (56-100X)

448 - 800X = 100X

448 = 900X

0.50g = X

In the second extraction, you will extract 0.50g of material

Thus, after the two extraction you will lost:

4.44g + 0.50g = 4.94g of material

6 0

3 years ago

Explan respinsible behaviour inthe computer​

Explan respinsible behaviour inthe computer