<u>Answer:</u> The concentration of nitrogen dioxide at equilibrium is 0.063 M
<u>Explanation:</u>
We are given:
Initial concentration of nitrogen dioxide = 0.0250 M
Initial concentration of dinitrogen tetraoxide = 0.0250 M
For the given chemical equation:
<u>Initial:</u> 0.025 0.025
<u>At eqllm:</u> 0.025-x 0.025+2x
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
Neglecting the negative value of 'x', because concentration cannot be negative
So, equilibrium concentration of nitrogen dioxide = (0.025 + 2x) = [0.025 + 2(0.019)] = 0.063 M
Hence, the concentration of nitrogen dioxide at equilibrium is 0.063 M