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3 years ago

16. The structure shown is representative of which substituted hydrocarbon?

Chemistry

1 answer:

Viktor [21]3 years ago

5 0

Answer:

The answer is B. Ether

Explanation:

An atom of Oxygen between a carbon chain is called Ether

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2) Why does the bottle collapse when sitting on the counter?

icang [17]

Answer:

vapour pressure I's crushing the bottle

mark brainliest

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2 years ago

The outside temperature is 35°C. What is the temperature in K

Fittoniya [83]

Answer:

308.15

Explanation:

308.15K − 273.15 = 35°C

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3 years ago

Where would sound travel the slowest

viva [34]

Answer:

Wood

Explanation:

It is because sound is a longitudinal wave

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3 years ago

A chemical reaction produced 10.1 cm3 of nitrogen gas at 23 °C and 746 mmHg. What is the volume of this gas if the temperature a

adell [148]

Answer:

volume of gas = 9.1436cm³

Explanation:

We will only temperature from °C to K since the conversion is done by the addition of 273 to the Celsius value.

Its not necessary to convert pressure and volume as their conversions are done by multiplication and upon division using the combined gas equation, the factors used in their conversions will cancel out.

V1 =10.1cm³ , P1 =746mmHg, T1=23°C =23+273=296k

V2 =? , P2 =760mmmHg , T2=0°C = 0+273 =273K

Using the combined gas equation to calculate for V2;

$\frac{V1P1}{T1}=\frac{V2P2}{T2} \\ re-arranging, \\V2 =\frac{V1P1T2}{P2T1}$

$V2 =\frac{10.1*746*273}{760*296}$

V2=9.1436cm³

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4 years ago

how many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double dis

Ksenya-84 [330]

Balanced equation:
CaO + 2 HCl --> CaCl2 + H2O 
Calculate moles of each reactant: 
60.4 g CaO / 56.08 g/mol = 1.08 mol CaO 
69.0 g HCl / 36.46 g/mol = 1.89 mol HCl 

Identify the limiting reactant: 
Moles CaO needed to react with all HCl: 
1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO 
Because you have more CaO than that available, HCl is the limiting reactant. 

Calculate moles and mass CaCl2: 
1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2

8 0

3 years ago