Answer:
C. Lithium is most easily oxidized of the metals listed on the activity series and therefore it will most easily give electrons to metal cations
Explanation:
"Lithium" is a type of alkali metal that has a "single valence electron." Since it is a reactive element, it easily gives up an electron when it is combined with other elements. Such giving up of electron is meant to create compounds or bonds.
Among the common metals listed, "lithium" is the most easily oxidized. This means that it donates its electrons immediately. Such combination makes it exist as a<em> "cation"</em> or <em>"positively-charged."</em>
So, this explains the answer.
Answer:
71.372 g or 0.7 moles
Explanation:
We are given;
- Moles of Aluminium is 1.40 mol
- Moles of Oxygen 1.35 mol
We are required to determine the theoretical yield of Aluminium oxide
The equation for the reaction between Aluminium and Oxygen is given by;
4Al(s) + 3O₂(g) → 2Al₂O₃(s)
From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.
Therefore;
1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen
1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium
Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.
4 moles of aluminium reacts to generate 2 moles aluminium oxide.
Therefore;
Mole ratio Al : Al₂O₃ is 4 : 2
Thus;
Moles of Al₂O₃ = Moles of Al × 0.5
= 1.4 moles × 0.5
= 0.7 moles
But; 1 mole of Al₂O₃ = 101.96 g/mol
Thus;
Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol
= 71.372 g
The answer is C, good luck mate
Answer:
The answer to your question is pH = 0.686
Explanation:
Data
Acetic acid = 20 ml
Final volume = 1.7 L
pH = ?
density = 1.05 g/ml
Process
1.- Calculate the mass of acetic acid
density = mass / volume
mass = density x volume
mass = 1.05 x 20
mass = 21 g
2.- Calculate the moles of acetic acid (CH₃COOH)
Molar mass = (12 x 2) + (16 x 2) + (4 x 1)
= 24 + 32 + 4
= 60 g
60 g of acetic acid ---------------- 1 mol
21 g of acetic acid ----------------- x
x = (21 x 1) / 60
x = 0.35 moles
3.- Calculate the concentration
Molarity = 0.35 moles / 1.70 L
= 0.206
4.- Calculate the pH
pH = -log[0.206]
pH = 0.686
Yes. its a chemichal change.
