The reaction rates of the substances whether disappearance of a reactant or the appearance of a product are related to each other by the chemical reaction. The reaction rates are related as follows:
rate = rHBr / 2 = rBr2 = rH2
rH2 = 0.160 / 2 = 0.08 M/s
Hey there!:
is the solution <span>saturated , ie :
</span>They are the ones that have reached the exact solubility coefficient.<span>If we mix 64.4 g of KCl at 200.0 g of water at 20 º C, we'll see that the 32.2 g will dissolve and the remainder (32.2 g) will precipitate, forming the bottom body. In this case we will then have a solution saturated with background. However, if we want only the saturated solution, simply perform a simple filtration to separate the precipitate from the saturated solution.
hope this helps!</span>
Answer:
1.5057×10^22 atom
Explanation:
As we
1 mole of argon = 40 g of argon
i.e 40 g of argon = 1 mole of argon
1 g of argon = 1/40 mole of argon
1 mole of argon = 6.023×10^23 atom of argon
1/40 mole if argon = 1/40 ×6.023×10^23
= 1.5057×10^22
