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2 years ago

Nuclear changes differ from normal chemical changes in that all nuclear changes

Chemistry

1 answer:

kogti [31]2 years ago

8 0

Answer:

(1) Nuclear reactions entail a transition in the nucleus of an atom, which normally results in the formation of a new substance. Chemical reactions, on the other hand, only involve electron rearrangement and do not involve nuclei modifications. (4) Nuclear reactions are unaffected by the element's chemical form.

Explanation:

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Helpppooo give answer thanks

DaniilM [7]

Answer:

625 mL

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 250 mL

Molarity of stock solution (M₁) = 5 M

Molarity of diluted solution (M₂) = 2 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

5 × 250 = 2 × V₂

1250 = 2 × V₂

Divide both side by 2

V₂ = 1250 / 2

V₂ = 625 mL

Therefore, the volume of the diluted solution is 625 mL.

8 0

2 years ago

Which type of bond is present within a water molecule

krok68 [10]

Answer:

Covalent bonds

Explanation:

3 0

2 years ago

If the distance between two objects is decreased to - of the original

Charra [1.4K]

Answer:

The new force will be \frac{1}{100} of the original force.

Explanation:

In the context of this problem, we're dealing with the law of gravitational attraction. The law states that the gravitational force between two object is directly proportional to the product of their masses and inversely proportional to the square of a distance between them.

That said, let's say that our equation for the initial force is:

$F = G\frac{m_1m_2}{R^2}The problem states that the distance decrease to 1/10 of the original distance, this means:[tex]R_2 = \frac{1}{10}R$

And the force at this distance would be written in terms of the same equation:

$F_2 = G\frac{m_1m_2}{R_2^2}$

Find the ratio between the final and the initial force:

$\frac{F_2}{F} = \frac{G\frac{m_1m_2}{R_2^2}}{G\frac{m_1m_2}{R^2}}$

Substitute the value for the final distance in terms of the initial distance:

$\frac{F_2}{F} = \frac{G\frac{m_1m_2}{(\frac{R}{10})^2}}{G\frac{m_1m_2}{R^2}}$

Simplify:

$\frac{F_2}{F} = \frac{\frac{1}{100R^2}}{\frac{1}{R^2}}=\frac{1}{100}$

This means the new force will be \frac{1}{100} of the original force.

8 0

2 years ago

A 0.0372-m3 container is initially evacuated. Then, 4.65 g of water is placed in the container, and, after some time, all of the

Montano1993 [528]

Answer:

18.3 kilopascals

Explanation:

We are given that the volume of this container is 0.0372 meters^3, that the mass of water is 4.65 grams, and that the temperature of this water vapor ( over time ) is 368 degrees Kelvins. This is a problem where the ideal gas law is an " ideal " application.

_______________________________________________________

First calculate the number of moles present in the water ( H2O ). Water has a mass of 18, so it should be that n, in the ideal gas law - PV = nRT, is equal to 4 / 18. It is the amount of the substance.

We now have enough information to solve for P in PV = nRT,

P( 0.0372 ) = 4 / 18( 8.314 )( 368 ),

P ≈ 18,276.9

Pressure ≈ 18.3 kilopascals

<u><em>Hope that helps!</em></u>

5 0

2 years ago

Describe the trend in electronegativity of the elements ?

dalvyx [7]

Answer:

On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.

Explanation:

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4 0

2 years ago