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meriva
3 years ago
15

Nuclear changes differ from normal chemical changes in that all nuclear changes

Chemistry
1 answer:
kogti [31]3 years ago
8 0

Answer:

(1) Nuclear reactions entail a transition in the nucleus of an atom, which normally results in the formation of a new substance. Chemical reactions, on the other hand, only involve electron rearrangement and do not involve nuclei modifications. (4) Nuclear reactions are unaffected by the element's chemical form.

Explanation:

Hope this helps!

Please mark me as Brainlinieast.

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What is the purpose of adding phenolphthalein to your Erlenmeyer flask prior to starting a titration?
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Answer:

a. The phenolphthalein acts as a color changing indicator to signal the endpoint of the reaction.

Explanation:

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In this way it helps visually to notice when the final point of the titration has been reached.

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Nucleic acids are chains of 5-carbon sugars linked by ____ bonds with an organic base protruding from each sugar.
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<span>B) phosphodiester </span> is the correct answer
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3 years ago
What is the percent by mass of a solution containing 4. 0g of solute in 100g of water? (Percent by mass formula: (mass of solute
Hoochie [10]
B
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mass of solution - 100g + 4.0g = 104g
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5 0
2 years ago
Cirrhosis is a disease that affects which of the listed organs?
Inessa [10]
Cirrhosis is a disease that affects the liver
4 0
3 years ago
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What is the correct equilibrium constant expression for the following heterogeneous equilibrium? 4HCl (g) + O2 (g) ⇄ 2H2O (l) +
gizmo_the_mogwai [7]

Answer:

Kc=[Cl2]2/[HCl]4[O2]

Explanation:

Hello,

In this case, the law of mass action, allows us to study the mathematical expression regarding an equilibrium chemical reaction allowing us to see a relationship between the equilibrium constant and the concentration of both the products and reactants at equilibrium for either gaseous or aqueous substances only. Such relationship is assembled as the quotient between the concentration of products at equilibrium over the concentration of reactants at equilibrium equaling the equilibrium constant. Thus, for the given chemical reaction, such expression will have the concentration of chlorine at the numerator and both the concentrations of hydrogen chloride and oxygen at the denominator since water is liquid so it is not included in the shown below equation:

Kc=\frac{[Cl]^2}{[HCl]^4[O_2]}

Therefore the answer is: Kc=[Cl2]2/[HCl]4[O2].

Best regards.

5 0
3 years ago
Read 2 more answers
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