Answer:
The average linear velocity (inches/second) of the golf club is 136.01 inches/second
Explanation:
Given;
length of the club, L = 29 inches
rotation angle, θ = 215⁰
time of motion, t = 0.8 s
The angular speed of the club is calculated as follows;

The average linear velocity (inches/second) of the golf club is calculated as;
v = ωr
v = 4.69 rad/s x 29 inches
v = 136.01 inches/second
Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second
<h2>
Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>
Explanation:
The half-life
of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.
In this case, we are given the half life of two elements:
beryllium-13: 
beryllium-15: 
As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?
We can find it out by the following expression:

Where
is the amount we want to find:


Finally:

Therefore:
The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.
Average speed= total distance/total time =12km/h
Answer:

Explanation:
Torque is defined as the cross product between the position vector ( the lever arm vector connecting the origin to the point of force application) and the force vector.

Due to the definition of cross product, the magnitude of the torque is given by:

Where
is the angle between the force and lever arm vectors. So, the length of the lever arm (r) is minimun when
is equal to one, solving for r:

Answer:
h = 10000 m
Explanation:
The pressure applied at a depth of the liquid is given by:
P =ρgh
where,
P = Maximum Pressure to Survive = (1000)(Atmospheric Pressure)
P = (1000)(101325 Pa) = 1.01 x 10⁸ Pa
ρ = Density of sea water = 1025 kg/m³
g = 9.8 m/s²
h = maximum depth to survive = ?
Therefore,
1.01 x 10⁸ Pa = (1025 kg/m³)(9.8 m/s²)h
h = (1.01 x 10⁸ Pa)/(1025 kg/m³)(9.8 m/s²)
<u>h = 10000 m</u>